我正在尝试找到正确的方法，以便能够在确定后保存力图节点布局位置，然后重新加载该布局并从相同的稳定状态重新开始。
我试图通过克隆包含图表的 DOM 元素、删除它然后重新加载它来做到这一点。
我可以做到这一点，部分如下所示： -
_clone = $('#chart').clone(true,true);
$('#chart').remove();
选择包含的 div，克隆它并删除它，然后再删除
var _target = $('#p1content');
_target.append(_clone);
选择div用于保存图表的那个并重新加载它。重新加载的图表是固定的。
我不知道如何重新连接力量以允许操纵继续进行。这可能吗？我想保留节点的固定位置。
另一种可能性，我可以重新加载节点位置并以低 alpha 启动力吗？
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>D3: Force layout</title>
<script src="./jquery-2.0.3.min.js" type="text/javascript"></script>
<script type="text/javascript" src="../d3.v3.js"></script>
<style type="text/css">
/* No style rules here yet */
</style>
</head>
<body>
<div data-role="content" id="p1content">
<div id="chart"></div>
</div>
<script type="text/javascript">
//Width and height
var w = 800;
var h = 600;
//Original data
var dataset = {
nodes: [
{ name: "Adam" },
{ name: "Bob" },
{ name: "Carrie" },
{ name: "Donovan" },
{ name: "Edward" },
{ name: "Felicity" },
{ name: "George" },
{ name: "Hannah" },
{ name: "Iris" },
{ name: "Jerry" }
],
edges: [
{ source: 0, target: 1 },
{ source: 0, target: 2 },
{ source: 0, target: 3 },
{ source: 0, target: 4 },
{ source: 1, target: 5 },
{ source: 2, target: 5 },
{ source: 2, target: 5 },
{ source: 3, target: 4 },
{ source: 5, target: 8 },
{ source: 5, target: 9 },
{ source: 6, target: 7 },
{ source: 7, target: 8 },
{ source: 8, target: 9 }
]
};
//Initialize a default force layout, using the nodes and edges in dataset
var force = d3.layout.force()
.nodes(dataset.nodes)
.links(dataset.edges)
.size([w, h])
.linkDistance([100])
.charge([-100])
.start();
var colors = d3.scale.category10();
//Create SVG element
var svg = d3.select("#chart")
.append("svg")
.attr("width", w)
.attr("height", h);
//Create edges as lines
var edges = svg.selectAll("line")
.data(dataset.edges)
.enter()
.append("line")
.style("stroke", "#ccc")
.style("stroke-width", 1);
//Create nodes as circles
var nodes = svg.selectAll("circle")
.data(dataset.nodes)
.enter()
.append("circle")
.attr("r", 10)
.style("fill", function(d, i) {
return colors(i);
})
.call(force.drag);
//Every time the simulation "ticks", this will be called
force.on("tick", function() {
edges.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
nodes.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});
// After 5 secs clone and remove DOM elements
setTimeout(function() {
_clone = $('#chart').clone(true,true);
$('#chart').remove();
}, 5000);
//After 10 secs reload DOM
setTimeout(function() {
var _target = $('#p1content');
_target.append(_clone);
// WHAT NEEDS TO GO HERE TO RECOUPLE THE FORCE?
}, 10000);
</script>
</body>
</html>
在我放的地方添加了这个 // 什么需要去这里来恢复力量？
这似乎可以拾取已恢复的现有元素并将原力重新耦合到它停止将力节点等传递到超时函数的位置
force = d3.layout.force()
.nodes(dataset.nodes)
.links(dataset.edges)
.size([w, h])
.linkDistance([100])
.charge([-100])
.start();
colors = d3.scale.category10();
//Create SVG element
svg = d3.select("#chart");
//Create edges as lines
edges = svg.selectAll("line")
.data(dataset.edges);
//Create nodes as circles
nodes = svg.selectAll("circle")
.data(dataset.nodes)
.call(force.drag);
//Every time the simulation "ticks", this will be called
force.on("tick", function() {
edges.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
nodes.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});