-2

例如：考虑 file1.txt 的内容：

1   0   9227    1152    34  2
2   111 7622    1120    34  2
3   68486   710 1024    14  2
6   265065  3389    800 22  2
7   393152  48438   64  132 3
8   412251  46744   64  132 3
9   430593  50866   256 95  4
10  430730  10770   256 95  4
11  433750  12701   256 14  3
12  437926  2794    64  34  2
13  440070  43  32  96  3
14  440102  44  32  96  3
15  440357  43  32  96  3
16  440545  43  32  96  3
17  440599  43  32  96  3
18  440625  43  32  96  3
19  440999  84  32  96  0
20  441574  44  32  96  3
`````````````````````````````````````````
`````````````````````````````````````````
`````````````````````````````````````````
`````````````````````````````````````````
`````````````````````````````````````````
`````````````````````````````````````````

其中包含n具有6字段的作业（即列（0-5））

现在，例如，我将前 19 个工作作为历史。然后我需要从 20 日开始阅读，以此类推，比较3,4,5历史中与上述职位匹配的列。如果它像示例中的第 20 个作业与历史记录中的 6(13,14,15,16,17,18) 6 个作业匹配，那么现在我需要创建一个仅包含 column2 的匹配作业的列表？

任何人都可以建议一个python中的代码，我可以通过它阅读第20行并与上述历史记录进行比较并继续21,22,23------------------直到到达文件末尾......

4

1 回答 1

2

检查这是否适合您：

>>> history = {}
>>> historycount = 17
>>> for line in open("filename"):
    job = line.split()
    jobmatch_criteria = '-'.join(job[-3:])
    if historycount > 0:
        history.setdefault(jobmatch_criteria,[]).append(job)
        historycount -= 1
    else:
        print "Job", job[0], "Matched with:", '\n\t'.join(' '.join(i) for i in history[jobmatch_criteria]) if jobmatch_criteria in history else "None"


Job 20 Matched with: 13 440070 43 32 96 3
    14 440102 44 32 96 3
    15 440357 43 32 96 3
    16 440545 43 32 96 3
    17 440599 43 32 96 3
    18 440625 43 32 96 3
Job 21 Matched with: 6 265065 3389 800 22 2

我用这个作为测试数据：

1   0   9227    1152    34  2
2   111 7622    1120    34  2
3   68486   710 1024    14  2
6   265065  3389    800 22  2
7   393152  48438   64  132 3
8   412251  46744   64  132 3
9   430593  50866   256 95  4
10  430730  10770   256 95  4
11  433750  12701   256 14  3
12  437926  2794    64  34  2
13  440070  43  32  96  3
14  440102  44  32  96  3
15  440357  43  32  96  3
16  440545  43  32  96  3
17  440599  43  32  96  3
18  440625  43  32  96  3
19  440999  84  32  96  0
20  441574  44  32  96  3
21  265065  3389    800 22  2
于 2013-08-13T09:14:52.327 回答