11

我从 java 代码tableHiveCell和tableHiveWiFi.

当我尝试运行以下 sql 命令时：

select count(UEs.cnc) as 'Active UEs' 
                      ^
from 
(select distinct cnc from tableHiveCell wifi  
  union 
 select distinct cnc from tableHiveCell cell)
 as UEs;

我收到一个错误：

java.sql.SQLException:
Query returned non-zero code: 11,
cause: FAILED: Parse Error: line 1:22 mismatched input 'as' expecting FROM near ')' in from clause
at org.apache.hadoop.hive.jdbc.HiveStatement.executeQuery(HiveStatement.java:189).

我错过了什么？

[编辑 1]

我试过了：

select count(UEs.cnc) as 'Active UEs' 
                      ^
from 
(select distinct cnc from tableHiveCell wifi)  
  union 
 (select distinct cnc from tableHiveCell cell)
 as UEs;

同样的错误

[编辑 2]

我试过了：

select count(UEs.cnc) as Active_UEs
 from (select distinct cnc from tableHiveCell wifi
  union ALL 
 select distinct cnc from tableHiveCell cell) as UEs;
                                              ^

得到相同的错误，但最后一个as：

 line 1:142 mismatched input 'as' expecting Identifier near ')' in subquery source
4

1 回答 1

7

如答案表单中所要求的：Hadoop 似乎通过AS子查询上的关键字存在别名问题，您可以轻松地在没有AS关键字的情况下分配别名。

示例可以在这里找到：https ://www.inkling.com/read/hadoop-definitive-guide-tom-white-3rd/chapter-12/querying-data

并为未来的访问者引用（参见mt子查询的别名）：

SELECT station, year, AVG(max_temperature)
FROM (
  SELECT station, year, MAX(temperature) AS max_temperature
  FROM records2
  WHERE temperature != 9999
    AND (quality = 0 OR quality = 1 OR quality = 4 OR quality = 5 OR quality = 9)
  GROUP BY station, year
) mt
GROUP BY station, year;
于 2013-08-13T10:38:40.893 回答