我想用相同的请求获取'a.com/a.html'和'a.com/b.html'的内容我的代码是
uri = URI.parse("http://www.sample.com/sample1.html")
http = Net::HTTP.new(uri.host, uri.port)
request = Net::HTTP::Get.new(uri.request_uri)
# request.initialize_http_header({"User-Agent" => "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/28.0.1500.95 Safari/537.36"})
result = http.request(request).body
我应该更改请求的路径吗?或任何其他想法?