0
<script src="jquery.js"></script>
<script>
    function loadContent() {
        $("#includedContent").load("../Projects/menu.html"); //  Not working
    }    
</script> 

<div id="includedContent"></div>

<script>
    loadContent()
</script> 
4

1 回答 1

0
$(document).ready(function(){
    $('#includedContent').load("../Projects/menu.html", function() {
       //stuff
    });
});
于 2013-08-13T07:54:11.843 回答