好的,所以我的问题是我在 ListBox 内的 DataTemplate 内有 Grid。当我更改方向时,我需要更改网格的列定义,但不幸的是,当我将 x:Name 分配给网格时,我无法在后面的代码中访问它......有没有特定的方法可以做到这一点?我需要设置名称为“test”的网格的列定义。有代码:
<Grid x:Name="EmployeesGrid" Grid.Row="1" Height="550" VerticalAlignment="Bottom">
<Grid.ColumnDefinitions>
<ColumnDefinition Width="280"/>
<ColumnDefinition Width="195"/>
</Grid.ColumnDefinitions>
<ScrollViewer HorizontalScrollBarVisibility="Visible" VerticalScrollBarVisibility="Visible" Grid.ColumnSpan="2" Margin="0,0,0,0">
<ListBox Height="605" HorizontalAlignment="Left" Margin="0,6,0,0" Name="listBox1" VerticalAlignment="Top" Width="480">
<ListBox.ItemTemplate>
<DataTemplate>
<Grid x:Name="test">
<Grid.ColumnDefinitions>
<ColumnDefinition Width="280"/>
<ColumnDefinition Width="195"/>
</Grid.ColumnDefinitions>
<TextBlock Text="{Binding FullName}" FontSize="20" Grid.Column="0" HorizontalAlignment="Center"/>
<TextBlock Text="{Binding BranchName}" FontSize="20" Grid.Column="1" HorizontalAlignment="Center"/>
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
</ScrollViewer>
</Grid>