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我想将 parent.php 中的文本框值传递给我的弹出窗口（child_page.php）。以下是我的代码。parent.php-

<html>
<head>
<script type="text/javascript">

var popupWindow=null;

function child_open()
{ 

popupWindow =window.open('child_page.php',"_blank","directories=no, status=no, menubar=no, scrollbars=yes, resizable=no,width=600, height=280,top=200,left=200");

}
function parent_disable() {
if(popupWindow && !popupWindow.closed)
popupWindow.focus();
}
</script>

 <input type="text" name="myTextField" id="myTextField" required="required"/>


</head>
<body onFocus="parent_disable();" onclick="parent_disable();">
    <a href="javascript:child_open()">Click me</a>
</body>    

</html>

child_page.php

<h1>child page</h1>


<script>
    window.onunload = refreshParent;
    function refreshParent() {
        window.opener.location.reload();
    }
    var x=parent.document.getElementById('myTextField').value

    <?php echo x; ?>
</script>

<?php 

//how do I get the textbox value here.

    ?>

我用谷歌搜索并尝试做到这一点。由于我对 java 脚本知之甚少，因此无法将这些答案集中在一起作为解决方案。

4

1 回答 1

1

您的 html 中有很多错误。您正在关闭 head 标签之前编写输入元素。将其移入体内。并尝试这样的事情：

<html>
<head>
<script type="text/javascript">

    var popupWindow=null;

    function child_open(val){ 
        popupWindow =window.open('child_page.php' + "?val=" + val,"_blank","directories=no, status=no, menubar=no, scrollbars=yes, resizable=no,width=600, height=280,top=200,left=200");
    }

    function parent_disable() {
        if(popupWindow && !popupWindow.closed)
            popupWindow.focus();
    }
</script>

</head>
<body onFocus="parent_disable();" onclick="parent_disable();">
    <input type="text" name="myTextField" id="myTextField" required="required"/>
    <a href="#" onclick="var val = document.getElementById('myTextField').value; child_open(val);return false">Click me</a>
</body>    

</html>

现在，您child_page.php可以使用$_GET['val'].

//child_page.php

<h1>child page</h1>
<?php $x = $_GET['val']; ?>
<script>
    window.onunload = refreshParent;
    function refreshParent() {
        window.opener.location.reload();
    }   
</script>

<?php echo $x; ?>
于 2013-08-13T03:41:19.577 回答