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我对 C++ 编程有些陌生，我被分配了一个练习，我得到了一个编译错误

我希望有人可以帮助我解决错误，或者让我了解它为什么会发生下面的代码 /* 练习 21 中级：声明一个名为 temperature 的七行两列 int 数组。程序应提示用户输入 7 天的最高和最低温度。将最高温度存储在数组的第一列中。将最低温度存储在第二列中。程序应显示平均高温和平均低温。显示平均温度，保留一位小数。*/

#include <iostream>
#include <iomanip>
using namespace std;

//function prototype
void calcAverage(double temperatures[7][2]);

main()
{
double temperatures[7][2] = {0};

float high = 0.0;
float low = 0.0;
double high_average = 0.0;
double low_average = 0.0;



cout << "Please enter the high then low for the last 7 days " <<endl;

for(int x = 0; x < 6; x += 1)
{
    cout << "Please enter the High for day: "<< x+1<<": ";
    cin >> high;
    temperatures[0][x] = high;
}
for(int x = 0; x < 6; x += 1)
{
    cout << "Please enter the Low for day: "<< x+1<<": ";
    cin >> low;
    temperatures[1][x] = high;
}
//Error is here
calcAverage(high_average, low_average);
// end error   
system("pause");        
}


void calcAverage(double temperatures[6][1],double &high_average, double &low_average)
{
float accumulator = 0.0;
//for hot average  
for(int x = 0; x < 6; x += 1)
{
    accumulator += temperatures[0][x];
}
    high_average = accumulator;

// for cold average 
    accumulator = 0.0;
for(int x = 0; x < 6; x += 1)
{
    accumulator += temperatures[1][x];
}
    low_average = accumulator;
}

44 不能为参数转换double' todouble ( )[2]' 1' tovoid calcAverage(double ( )[2])'

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1 回答 1

2 
void calcAverage(double temperatures[7][2]);

好的，calcAverage需要一个二维的双精度数组。

calcAverage(high_average, low_average);

但是你通过了两次双打。

void calcAverage(double temperatures[6][1],double &high_average, double &low_average)

现在它需要一个二维数组和两个引用。

从这三个中选择一个并坚持下去。

于 2013-08-13T03:32:27.797 回答