php - 电子请假申请数据库设计

Question

我目前正在处理休假申请（这是我的电子调度项目的一个子集），我的数据库设计如下：

event (event_id, dtstart, dtend... *follows icalendar standard*)

event_leave (event_id*, leave_type_id*, total_days)

_leave_type (leave_type_id, name, max_carry_forward)

_leave_allocation (leave_allocation_id, leave_type_id*, name, user_group_id, total_days, year)

_leave_carry_forward(leave_carry_forward_id, leave_type_id*, user_id, year)

stackoverflow 中是否有人也在开发电子休假应用程序？介意分享您的数据库设计，因为我正在寻找比我更好的设计。我当前设计的问题只出现在年初系统正在计算可以结转的天数时。

总共我必须运行 1 + {$number_of users} * 2 查询（第一个查询分配规则的数量和最大结转配额。然后对于每个用户，我需要找出余额，并且然后将余额插入数据库）

Answer 1

我没有很好地遵循架构（看起来每个 leave_type 都会结转？事件*表上没有用户？）但您应该能够在任何时间点动态得出余额 - 包括跨年.

AAMOF，规范化规则将要求您能够得出平衡。如果您随后选择非规范化以提高性能，则取决于您，但设计应支持计算查询。鉴于此，计算年终结转是基于单个集合的查询。

编辑：我不得不稍微更改架构以适应这一点，我选择规范化以使逻辑更容易 - 但如果需要，您可以在此过程中插入非规范化以提高性能：

首先是对这种情况很重要的表......希望我的伪语法会有意义：

User { User_Id (PK) }

// Year may be a tricky business logic issue here...Do you charge the Start or End year
// if the event crosses a year boundary? Or do you just do 2 different events?
// You want year in this table, though, so you can do a FK reference to Leave_Allocation
// Some RDBMS will let you do a FK from a View, though, so you could do that
Event { Event_Id (PK), User_Id, Leave_Type_Id, Year, DtStart, DtEnd, ... 
   // Ensure that events are charged to leave the user has
   FK (User_Id, Leave_Type_Id, Year)->Leave_Allocation(User_Id, Leave_Type_Id, Year)
}

Leave_Type { Leave_Type_Id, Year, Max_Carry_Forward 
   // Max_Carry_Forward would probably change per year
   PK (Leave_Type_Id, Year)
}

// Starting balance for each leave_type and user, per year
// Not sure the name makes the most sense - I think of Allocated as used leave,
// so I'd probably call this Leave_Starting_Balance or something
Leave_Allocation { Leave_Type_Id (FK->Leave_Type.Leave_Type_Id), User_Id (FK->User.User_Id), Year, Total_Days 
   PK (Leave_Type_Id, User_Id, Year)
   // Ensure that leave_type is defined for this year
   FK (Leave_Type_Id, Year)->Leave_Type(Leave_Type_Id, Year)
}

然后，视图（您可能希望在其中应用一些非规范化）：

/* Just sum up the Total_Days for an event to make some other calcs easier */
CREATE VIEW Event_Leave AS
   SELECT
      Event_Id,
      User_Id,
      Leave_Type_Id,
      DATEDIFF(d, DtEnd, DtStart) as Total_Days,
      Year
   FROM Event

/* Subtract sum of allocated leave (Event_Leave.Total_Days) from starting balance (Leave_Allocation) */
/* to get the current unused balance of leave */
CREATE VIEW Leave_Current_Balance AS
   SELECT
      Leave_Allocation.User_Id,
      Leave_Allocation.Leave_Type_Id,
      Leave_Allocation.Year,
      Leave_Allocation.Total_Days - SUM(Event_Leave.Total_Days) as Leave_Balance
   FROM Leave_Allocation
   LEFT OUTER JOIN Event_Leave ON
      Leave_Allocation.User_Id = Event_Leave.User_Id
      AND Leave_Allocation.Leave_Type_Id = Event_Leave.Leave_Type_Id
      AND Leave_Allocation.Year = Event_Leave.Year
   GROUP BY
      Leave_Allocation.User_Id,
      Leave_Allocation.Leave_Type_Id,
      Leave_Allocation.Year,
      Leave_Allocation.Total_Days

现在，我们的离开结转查询只是截至 1 月 1 日午夜的当前余额的最小值或最大结转。

   SELECT
      User_Id,
      Leave_Type_Id,
      Year,
      /* This is T-SQL syntax...your RDBMS may be different, but should be able to do the same thing */
      /* If not, you'd do a UNION ALL to Max_Carry_Forward and select MIN(BalanceOrMax) */
      CASE 
         WHEN Leave_Balance < Max_Carry_Forward 
             THEN Leave_Balance 
         ELSE 
             Max_Carry_Forward 
      END as Leave_Carry_Forward
  FROM Leave_Current_Balance
  JOIN Leave_Type ON
      Leave_Current_Balance.Leave_Type_Id = Leave_Type.Leave_Type_Id
      /* This assumes max_carry_forward is how much you can carry_forward into the next year */
      /* eg,, a max_carry_forward of 300 hours for year 2008, means I can carry_forward up to 300 */
      /* hours into 2009. Otherwise, you'd join on Leave_Current_Balance.Year + 1 if it's how much */
      /* I can carry forward into *this* year. */
      AND Leave_Current_Balance.Year = Leave_Type.Year

因此，在年底，您将在新的一年将结转余额重新插入 LeaveAllocation。

Answer 2

总会有更好的设计！！

你目前的设计有效吗？您期望有多少用户（即，您必须运行 x 千次查询是否重要）。

如果当前设计的问题只是在年初，那么也许你可以忍受它！

干杯

纽西兰

Answer 3

关于我的数据库设计和一些用例的进一步说明。

表设计

这是存储事件的主表（基本上基于 iCalendar 架构）。事件可以是典型事件，也可以是会议、公共假期等。

event (event_id (PK), dtstart, dtend, ... --other icalendar fields--)

如果特定类型的事件有我必须跟踪的额外信息，我会用另一张桌子装饰它。例如，存储电子休假特定信息的表。（total_days 不是作为要求的一部分的计算字段）

event_leave (event_id (PK/FK->event), total_days, leave_type_id (FK->leave_type))

请假类型表存储有关每个请假类型的一些信息。例如，应用程序是否需要批准/推荐等。除此之外，它还存储允许的最大结转。我假设最大结转不会经常改变。

leave_type (leave_type_id (PK), name, require_support, require_recommend, max_carry_forward)

用户被分成组，每个组将被赋予一些休假类型的可休假天数。存储在此表中的数据将每年填充一次（每年更新一次）。它只存储每个组的休假数，而不是每个用户。

leave_allocation (leave_allocation_id, year(PK), leave_type_id (PK/FK->leave_type), total_days, group_id)

接下来是存储结转信息的表。该表将每年为每个用户填充一次。该表将每年填充一次，因为动态计算并不容易。为用户计算 leave_carry_forward 的公式为：

leave_carry_forward(2009) = min(leave_allocation(2008) + leave_carry_forward(2007) - leave_taken(2008), maximum_carry_forward());

leave_carry_forward (leave_carry_forward_id, user_id, year, total_days)

一些示例用例和解决方案

计算余额 (WIP)

为了计算余额，我对声明如下的视图进行查询

DROP VIEW IF EXISTS leave_remaining_days;
CREATE OR REPLACE VIEW leave_remaining_days AS
    SELECT      year, user_id, leave_type_id, SUM(total_days) as total_days
    FROM        (
            SELECT  allocated.year, usr.uid AS "user_id", allocated.leave_type_id, 
                allocated.total_days
            FROM    users usr
                JOIN app_event._leave_allocation allocated
                ON allocated.group_id = usr.group_id
            UNION
            SELECT  EXTRACT(year FROM event.dtstart) AS "year", event.user_id, 
                leave.leave_type_id, leave.total_days * -1 AS total_days
            FROM    app_event.event event
                LEFT JOIN app_event.event_leave leave
                ON event.event_id = leave.event_id
            UNION
            SELECT  year, user_id, leave_type_id, total_days
            FROM    app_event._leave_carry_forward
        ) KKR
    GROUP BY    year, user_id, leave_type_id;

在年初填充 leave_allocation 表

public function populate_allocation($year) {
    return $this->db->query(sprintf(
        'INSERT INTO %s (%s)' .
            "SELECT '%s' AS year, %s " .
            'FROM   %s ' .
            'WHERE  "year" = %s',
        'event_allocation',
        'year, leave_type_id, total_days ...', //(all the fields in the table)
        empty($year) ? date('Y') : $year,
        'leave_type_id, total_days, ..', //(all fields except year)
        $this->__table,
        empty($year) ? date('Y') - 1 : $year - 1
    ))
    ->count() > 0;  // using the database query builder in Kohana PHP framework
}

在年初填充 leave_carry_forward 表

找出分配给用户的休假类型

我可能需要重命名这个视图（我不擅长命名东西......）。它实际上是一个用户的 leave_allocation 表。

DROP VIEW IF EXISTS user_leave_type;
CREATE OR REPLACE VIEW user_leave_type AS
    SELECT  la.year, usr.uid AS user_id, lt.leave_type_id, lt.max_carry_forward
    FROM    users usr
            JOIN app_event._leave_allocation la
                JOIN app_event._leave_type lt
                ON la.leave_type_id = lt.leave_type_id
            ON usr.group_id = la.group_id

实际查询

INSERT INTO leave_carry_forward (year, user_id, leave_type_id, total_days)
    SELECT      '{$this_year}' AS year, user_id, leave_type_id, MIN(carry_forward) AS total_days
    FROM        (
                    SELECT  year, user_id, leave_type_id, total_days AS carry_forward
                    FROM    leave_remaining_days
                    UNION
                    SELECT  year, user_id, leave_type_id, max_carry_forward AS carry_forward
                    FROM    user_leave_type
                ) KKR
    WHERE       year = {$last_year}
    GROUP BY    year, user_id, leave_type_id;