140

我试图使用一个 API 使用下面的示例结构来返回他们的 json

[
   {
      "customer":{
         "first_name":"Test",
         "last_name":"Account",
         "email":"test1@example.com",
         "organization":"",
         "reference":null,
         "id":3545134,
         "created_at":"2013-08-06T15:51:15-04:00",
         "updated_at":"2013-08-06T15:51:15-04:00",
         "address":"",
         "address_2":"",
         "city":"",
         "state":"",
         "zip":"",
         "country":"",
         "phone":""
      }
   },
   {
      "customer":{
         "first_name":"Test",
         "last_name":"Account2",
         "email":"test2@example.com",
         "organization":"",
         "reference":null,
         "id":3570462,
         "created_at":"2013-08-12T11:54:58-04:00",
         "updated_at":"2013-08-12T11:54:58-04:00",
         "address":"",
         "address_2":"",
         "city":"",
         "state":"",
         "zip":"",
         "country":"",
         "phone":""
      }
   }
]

JSON.net 可以很好地使用类似以下结构的东西 

{
    "customer": {
        ["field1" : "value", etc...],
        ["field1" : "value", etc...],
    }
}

但我不知道如何让它对提供的结构感到满意。

使用默认的 JsonConvert.DeserializeObject(content) 会产生正确的客户数量，但所有数据都为空。

执行 CustomerList（如下）会导致“无法反序列化当前 JSON 数组”异常

public class CustomerList
{
    public List<Customer> customer { get; set; }
}

想法？

4

5 回答 5

210

您可以创建一个新模型来反序列化您的 JSON CustomerJson：

    public class CustomerJson
    {
        [JsonProperty("customer")]
        public Customer Customer { get; set; }
    }

    public class Customer
    {
        [JsonProperty("first_name")]
        public string Firstname { get; set; }

        [JsonProperty("last_name")]
        public string Lastname { get; set; }

        ...
    }

您可以轻松地反序列化您的 JSON：

JsonConvert.DeserializeObject<List<CustomerJson>>(json);

文档：序列化和反序列化 JSON

于 2013-08-12T16:56:51.653 回答
49

对于那些不想创建任何模型的人，请使用以下代码：

var result = JsonConvert.DeserializeObject<
  List<Dictionary<string, 
    Dictionary<string, string>>>>(content);

注意：这不适用于您的JSON 字符串。这不是任何 JSON 结构的通用解决方案。

于 2014-06-30T07:47:51.520 回答
3

使用接受的答案，您必须使用 访问每条记录Customers[i].customer，并且您需要一个额外的CustomerJson类，这有点烦人。如果您不想这样做，可以使用以下方法：

public class CustomerList
{
    [JsonConverter(typeof(MyListConverter))]
    public List<Customer> customer { get; set; }
}

请注意，我使用的是List<>，而不是数组。现在创建以下类：

class MyListConverter : JsonConverter
{
    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        var token = JToken.Load(reader);
        var list = Activator.CreateInstance(objectType) as System.Collections.IList;
        var itemType = objectType.GenericTypeArguments[0];
        foreach (var child in token.Values())
        {
            var childToken = child.Children().First();
            var newObject = Activator.CreateInstance(itemType);
            serializer.Populate(childToken.CreateReader(), newObject);
            list.Add(newObject);
        }
        return list;
    }

    public override bool CanConvert(Type objectType)
    {
        return objectType.IsGenericType && (objectType.GetGenericTypeDefinition() == typeof(List<>));
    }
    public override bool CanWrite => false;
    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) => throw new NotImplementedException();
}
于 2018-03-02T18:17:02.030 回答
1

对上述内容稍作修改。我验证的 Json 格式是

{
    mycollection:{[
           {   
               property0:value,
               property1:value,
             },
             {   
               property0:value,
               property1:value,
             }
           ]

         }
       }

使用 AlexDev 的回应，我这样做了循环每个孩子，从中创建阅读器

 public partial class myModel
{
    public static List<myModel> FromJson(string json) => JsonConvert.DeserializeObject<myModelList>(json, Converter.Settings).model;
}

 public class myModelList {
    [JsonConverter(typeof(myModelConverter))]
    public List<myModel> model { get; set; }

}

class myModelConverter : JsonConverter
{
    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        var token = JToken.Load(reader);
        var list = Activator.CreateInstance(objectType) as System.Collections.IList;
        var itemType = objectType.GenericTypeArguments[0];
        foreach (var child in token.Children())  //mod here
        {
            var newObject = Activator.CreateInstance(itemType);
            serializer.Populate(child.CreateReader(), newObject); //mod here
            list.Add(newObject);
        }
        return list;
    }

    public override bool CanConvert(Type objectType)
    {
        return objectType.IsGenericType && (objectType.GetGenericTypeDefinition() == typeof(List<>));
    }
    public override bool CanWrite => false;
    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) => throw new NotImplementedException();

}
于 2018-11-08T19:05:45.483 回答
0

从 JC_VA 进一步修改，取他所拥有的，并将 MyModelConverter 替换为...

public class MyModelConverter : JsonConverter
{
    //objectType is the type as specified for List<myModel> (i.e. myModel)
    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        var token = JToken.Load(reader); //json from myModelList > model
        var list = Activator.CreateInstance(objectType) as System.Collections.IList; // new list to return
        var itemType = objectType.GenericTypeArguments[0]; // type of the list (myModel)
        if (token.Type.ToString() == "Object") //Object
        {
            var child = token.Children();
            var newObject = Activator.CreateInstance(itemType);
            serializer.Populate(token.CreateReader(), newObject);
            list.Add(newObject);
        }
        else //Array
        {
            foreach (var child in token.Children())
            {
                var newObject = Activator.CreateInstance(itemType);
                serializer.Populate(child.CreateReader(), newObject);
                list.Add(newObject);
            }
        }
        return list;

    }

    public override bool CanConvert(Type objectType)
    {
        return objectType.IsGenericType && (objectType.GetGenericTypeDefinition() == typeof(List<>));
    }
    public override bool CanWrite => false;
    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) => throw new NotImplementedException();
}

这应该适用于 json 是

myModelList{
 model: [{ ... object ... }]
}

或者

myModelList{
 model: { ... object ... }
}

它们最终都会被解析，就好像它们是

myModelList{
 model: [{ ... object ... }]
}
于 2019-12-16T16:26:23.077 回答