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我真的很难尝试使函数在 pthread 中循环。我的函数被这个 pthread 调用，它应该循环到无限，但是它只是没有发生。这就是我寻求帮助的原因。我使用以下代码创建了我的线程：

#include <pthread.h>  
#include <stdio.h>    
#include <string.h>
#include <stdlib.h>  

void *thread_s(void *params_s);

int main(int argc, char *argv[]) {
    int s1_hand = 0;
    pthread_t routines[1];
    printf("Creating Thread -> Main Thread Extremely Busy!\n");

    s1_hand = pthread_create(&(routines[0]), NULL, thread_s, (void *)&(routines[0]));

    if (s1_hand != 0) {
        printf("Not possible to create thread:[%s]\n", strerror(s1_hand));
        exit(EXIT_FAILURE);
    }

    void* result;
    if ((pthread_join(routines[0], &result)) == -1) {
        perror("Cannot join S thread");
        exit(EXIT_FAILURE);
    }

    pthread_exit(NULL);

    return 0;
}

我希望连续运行的功能是：

void *thread_s(void *params_s) {
    printf("Thread starting...\n");
    int fd, chars, pars, c_1, f_parse, pripa = 1;
    fd =  open("/dev/ttyUSB0", O_RDONLY | O_NOCTTY | O_SYNC);
    if (fd < 0){
        perror("Unable to open the fildes!");
        exit (EXIT_FAILURE);
    }
    FILE *stream_a, *stream_b;
    stream_a = fdopen(fd, "r");
    stream_b = fopen(FILE_II, "w+");
    if (stream_a == NULL && stream_b == NULL){
        perror("IMPOSSIBLE TO CREATE STREAMS");
        exit(EXIT_FAILURE);
    }
    c_1 = fgetc(stream_a);
    f_parse = lookatit(pripa, c_1, array);
    printf("First Parse Done -> (%i)\n", f_parse);
    while ((chars = fgetc(stream_a)) != EOF){
        pars = lookatit(0, (uint8_t)chars, array);
        if (pars == 1){
            printf("MESSAGE FOUND AND SAVED -> (%i)\n", parsing);
            fprintf(stream_b,"%.6f %.6f %.6f\n", array[0], array[1], array[2]);
        } else{
            printf("Looking for the Message: %i\n", parsing);
            continue;
        }
        chars++;
    }
    fflush(stream_b);
    fclose(stream_b);
    fclose(stream_a);
    close(fd);

    pthread_exit(NULL);

    return 0;
}

函数“lookatit”执行解析例程，当找到消息时返回 1，当未找到消息时返回 0。该函数在没有找到消息时完美循环，但是当它找到消息时，if 语句（第 22 行第二个代码）打印“MESSAGE FOUND AND SAVED”并立即终止程序。为什么我的程序会出现这种行为？

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