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/* 我在 SQLServer 2008 中查询以查找所有行的总和和行部分的总和时遇到问题。我用了ROW_NUMBER()，outer_apply，但是我不能解决问题。我在您的网站 stack_overflow 上搜索了几天，但找不到类似的东西。现在我什至不知道该怎么做。谁能帮我？？？

输入数据：Section Number、Initial Node、Final Node、Area，Section是两个节点之间的距离。每个节点都属于一个特定的区域。*/ 

A       B       C      D        
--------------------------------
Section Initial Final  Area     
Number  Node    Node                  
================================
1       0       1      0    
2       1       2      5    
3       2       3      3.1  
4       3       4      3.7  
5       4       5      2.7  
6       5       6      0    
7       6       7      4.1  
8       7       8      0    
9       8       9      2.8  
10      9       10     4.6  
11      10      11     3.2
12      11      12     3    
13      12      13     5    
14      13      14     3.5  
15      1       15     3    
16      15      16     5.6  
17      16      17     4.7  
18      17      18     2.8   
19      6       19     0    
20      19      20     3.8  
21      20      21     5    
22      19      22     2.9  
23      8       23     4.4

/* 需要计算一个累积面积（Area Cum），它属于网络中的每个节点。结果应该是*/

A       B       C     D        E        F
-----------------------------------------------------
Section Initial Final  Area     Area     Description
Number  Node    Node            Cum               
=====================================================
1       0       1       0       72.9    =SUM(D1:D23)
2       1       2       5       56.8    =SUM(D2:D14)+SUM(D19:D23)
3       2       3       3.1     51.8    =SUM(D3:D14)+SUM(D19:D23)
4       3       4       3.7     48.7    =SUM(D4:D14)+SUM(D19:D23)
5       4       5       2.7     45      =SUM(D5:D14)+SUM(D19:D23)
6       5       6       0       42.3    =SUM(D6:D14)+SUM(D19:D23)
7       6       7       4.1     30.6    =SUM(D7:D14)+D23
8       7       8       0       26.5    =SUM(D8:D14)+D23
9       8       9       2.8     22.1    =SUM(D9:D14)
10      9       10      4.6     19.3    =SUM(D10:D14)
11      10      11      3.2     14.7    =SUM(D11:D14)
12      11      12      3       11.5    =SUM(D12:D14)
13      12      13      5       8.5     =SUM(D13:D14)
14      13      14      3.5     3.5     =SUM(D14)
15      1       15      3       16.1    =SUM(D15:D18)
16      15      16      5.6     13.1    =SUM(D16:D18)
17      16      17      4.7     7.5     =SUM(D17:D18)
18      17      18      2.8     2.8     =SUM(D18)
19      6       19      0       11.7    =SUM(D19:D22)
20      19      20      3.8     8.8     =SUM(D20:D21)
21      20      21      5       5       =SUM(D21)
22      19      22      2.9     2.9     =SUM(D22)
23      8       23      4.4     4.4     =SUM(D23)
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1 回答 1

1

使用递归 CTE，您可以执行以下操作：

WITH RCTE AS 
(
    SELECT *, NULL S  FROM Table1
    UNION ALL
    SELECT t.*, COALESCE(r.S,r.SectionNumber) S FROM Table1 t
    INNER JOIN RCTE r ON r.FinalNode = t.InitialNode  
)
, CTE2 AS 
(
    SELECT S, SUM(Area) AS AreaCum FROM RCTE 
    GROUP BY S
)
SELECT t.*, COALESCE(c.AreaCum, t.Area) AreaCum FROM Table1 t
LEFT JOIN CTE2 c ON t.SectionNumber = c.S

SQLFiddle 演示

于 2013-08-12T15:31:18.070 回答