3

我正在尝试在 Pygame 中创建一个“雷达”。我无法旋转雷达的指针。我如何旋转它？

import pygame
from pygame.locals import *
SIZE = 800, 800
pygame.init()
screen = pygame.display.set_mode(SIZE)
FPSCLOCK = pygame.time.Clock()
done = False
screen.fill((0, 0, 0))
degree=0
while not done:
    for e in pygame.event.get():
        if e.type == QUIT or (e.type == KEYDOWN and e.key == K_ESCAPE):
            done = True
            break
    for x in range(1,400,10):
        pygame.draw.circle(screen,(255,255,255),(400,400),x,1)
    line = pygame.draw.line(screen,(10,100,10),(400,400),(400,0),3)
    pygame.transform.rotate(line,degree)
        pygame.display.flip()   
        degree+=5
        FPSCLOCK.tick(40)
4

2 回答 2

9

你需要计算你的开始和结束位置。

import math
import pygame
from pygame.locals import *

radar = (100,100)
radar_len = 50
x = radar[0] + math.cos(math.radians(angle)) * radar_len
y = radar[1] + math.sin(math.radians(angle)) * radar_len

# then render the line radar->(x,y)
pygame.draw.line(screen, Color("black"), radar, (x,y), 1)
于 2013-08-12T06:01:06.700 回答
2

您也可以只使用向量，一个用于“起点”，一个用于端点（即距起点的偏移量），然后旋转端点向量并将其添加到起点。

import sys
import pygame

pygame.init()

screen = pygame.display.set_mode((640, 480))
FPSCLOCK = pygame.time.Clock()
RED = pygame.Color("red")
startpoint = pygame.math.Vector2(320, 240)
endpoint = pygame.math.Vector2(170, 0)
angle = 0
done = False

while not done:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            done = True

    # % 360 to keep the angle between 0 and 360.
    angle = (angle+5) % 360
    # The current endpoint is the startpoint vector + the
    # rotated original endpoint vector.
    current_endpoint = startpoint + endpoint.rotate(angle)

    screen.fill((0, 0, 0))
    pygame.draw.line(screen, RED, startpoint, current_endpoint, 2)

    pygame.display.flip()
    FPSCLOCK.tick(30)

pygame.quit()
sys.exit()
于 2017-02-18T14:35:18.397 回答