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鉴于下面的 R3-GUI 代码,有没有办法访问计时器中剩余的时间?计时器 ID 由返回,set-timer但我不确定是否有什么可以用它做的?

set-timer [print "done"] 60

换句话说,我在一个假代码示例中寻找什么:

>> get-timer/time-remaining timer-id
== 0:0:21
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1 回答 1

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看源码就能找到答案set-timer

>> source set-timer
set-timer: make function! [[
    {Calls a function after a specified amount of time. Returns timer ID reference.}
    code [block!]
    timeout [number! time!]
    /repeat "Periodically repeat the function."
    /local t id
][
    t: now/precise
    if number? timeout [timeout: to time! timeout]
    sort/skip/compare append guie/timers compose/deep/only [(id: guie/timer-id: guie/timer-id + 1) [
        timeout (t + timeout)
        rate (all [
                repeat
                max 0:00 timeout
            ])
        callback (function [] code)
    ]] 2 2
    guie/timeout: true
    id
    ]
]

如果计时器仍在运行,它将在guie对象中。

>> guie/timers
== []

>> set-timer [print "done"] 2
== 5

>> guie/timers
== [5 [
    timeout 11-Aug-2013/22:41:13.381-5:00
    rate none
    callback make function! [[
        /local
    ][print "done"]]
]]

获取日期值将如下所示:

second select guie/timers timer-id
>>b: second select guie/timers 5
==11-Aug-2013/22:41:13.381-5:00
>>c: now/time - b/time
== 0:0:55

如果计时器已完成,do-events 会将其清除。如果事件没有运行,那么即使时间用完,计时器也会保持不变。

于 2013-08-12T03:46:05.863 回答