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问：为什么当我有多个整数时，我的 count 函数只能计数为 1？

代码：

import random

while True:
    value = 0
    count = 0
    right_counter = 0
    value = int(input("Enter the amount of questions would you like to answer: "))   
    AVG = right_counter / value
    if 0<=value<=10:
        for i in range(value):
            numb1 = random.randint(0, 12)
            numb2 = random.randint(0, 12)
            answer = numb1 * numb2
            AVG = right_counter / value



            problem = input("What is " + str(numb1) + " * " + str(numb2) + "? ")


            right_counter =+ 1


            if int(problem) == answer:
                print("You are Correct! Great Job!".format(right_counter))



            elif int(problem) > answer:
                print("Incorrect, Your answer is too high!")        


            elif int(problem) < answer:
                print("Incorrect, your answer is too low!")


        print("You got",right_counter,"out of",value,"correct, giving you an average of ",AVG,"")
        break


    else:
        print(" Error, Please type a number 1-10 ")

这是输出的样子：

输入您想回答的问题数量： 3
1 * 8 是多少？8
你说得对！做得好！
什么是 11 * 11？122
不正确，你的答案太高了！
什么是 1 * 7？7
你说得对！做得好！
你得到了 1 出 3 正确，给你平均 0.3333333333333333

我在Tutorial上找到了一些帮助，但我无法回答我的问题。

4

1 回答 1

2

漏洞：

right_counter =+ 1

这（偷偷地）等同于

right_counter = 1

你可能是说

right_counter += 1

您可能还想解决right_counter无论答案是否正确都会增加的逻辑问题。

于 2013-08-10T01:06:29.680 回答