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任何人都可以帮助将该代码从 java 转换为 php 吗？在下面阅读更多..

所以..我得到了这段代码..我正在尝试转换为php（5.{3,4,5}..没关系..我只是不想运行tomcat之类的东西）

  private static byte[] cAGLT(String lC){
      try {
          PublicKey PUBLIC_KEY;
          String key = "MIIBuDCCASwGByqGSM44BAEwggEfAoGBAP1/U4EddRIpUt9KnC7s5Of2EbdSPO9E.............long 593 char stuff here";
          KeyFactory keyFactory = KeyFactory.getInstance("DSA");
          PUBLIC_KEY = keyFactory.generatePublic(new X509EncodedKeySpec(Base64.decodeBase64(key.getBytes())));
          byte[] decodedBytes = Base64.decodeBase64(lC.getBytes());
          ByteArrayInputStream in = new ByteArrayInputStream(decodedBytes);
          DataInputStream dIn = new DataInputStream(in);
          int textLength = dIn.readInt();
          byte[] lT = new byte[textLength];
          dIn.read(lT);
          byte[] hash = new byte[dIn.available()];
          dIn.read(hash);
          try{
              Signature signature = Signature.getInstance("SHA1withDSA");
              signature.initVerify(PUBLIC_KEY);
              signature.update(lT);
              try{
                  signature.verify(hash);
              } catch (Exception e) {
                    throw e;
              }
          }catch (Exception e){
              throw e;
          }
          return lT;
      }catch (Exception e){
          throw new Error(e);
      }
  }

当我阅读它时，它从 x509 获取 public_key 并根据 x509 规范使用 public_key 解码它获得的字符串

我一直在尝试这样的 php 没有运气...

$key = "MIIBuDCCASwGByqGSM44BAEwggEfAoGBAP1/U4EddRIpUt9KnC7s5Of2EbdSPO9E.............long 593 char stuff here";
$key = "-----BEGIN PUBLIC KEY-----\n" . wordwrap($key, 64, "\n", true) . "-----END PUBLIC KEY-----"; // no \n before the ----END because it already has one
$key = openssl_pkey_get_public($key);
$key = openssl_pkey_get_details($key);
$key = "-----BEGIN PUBLIC KEY-----\n" . wordwrap(base64_encode($key['dsa']['pub_key']), 64, "\n", true)."\n-----END PUBLIC KEY-----";
        $data = null;
        openssl_public_decrypt($todecode, $data, $key);

哪个喊

PHP 警告：openssl_public_decrypt(): key parameter is not a valid public key

还尝试使用 phpseclib ( http://phpseclib.sourceforge.net/pear.htm )

$key = "MIIBuDCCASwGByqGSM44BAEwggEfAoGBAP1/U4EddRIpUt9KnC7s5Of2EbdSPO9E.............long 593 char stuff here";
$key = "-----BEGIN PUBLIC KEY-----\n" . wordwrap($key, 64, "\n", true) . "-----END PUBLIC KEY-----";
$data = null;
openssl_public_decrypt($licenseContent, $data, $key);

哪个喊

openssl_public_decrypt()：此 PHP 版本不支持密钥类型！

像这样：

include('BigInteger.php');
include('ASN1.php');
include('X509.php');
$key = "MIIBuDCCASwGByqGSM44BAEwggEfAoGBAP1/U4EddRIpUt9KnC7s5Of2EbdSPO9E.............long 593 char stuff here";
$key = "-----BEGIN CERTIFICATE-----\n" . wordwrap($key, 64, "\n", true) . "-----END CERTIFICATE-----";
$x509 = new File_X509();
$cert = $x509->loadX509($key);
print_r($cert);

什么都没有喊……还有：

$key = "MIIBuDCCASwGByqGSM44BAEwggEfAoGBAP1/U4EddRIpUt9KnC7s5Of2EbdSPO9E.............long 593 char stuff here";
$key = "-----BEGIN CERTIFICATE-----\n" . wordwrap($key, 64, "\n", true) . "-----END CERTIFICATE-----";
echo openssl_x509_read($key);

openssl_x509_read()：提供的参数不能被强制转换为 X509 证书！

我没主意了...

任何人都可以帮助将该代码从 java 转换为 php 吗？

任何想法.. 非常感谢。如果这已经得到回答，请不要拍摄（我做了谷歌并找到了信息，但没有运气尝试申请。提前致谢。

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0 回答 0