2

我有一个包含我的服务器状态的表

create table ServerStatus
(
    ServerId int, 
    StartTime datetime, 
    Seconds int,
    [State] char(8) 
)

我想要一个给定开始和结束日期的查询，它将总结服务器在此期间在每个状态中花费的时间。我还希望查询返回服务器处于未知状态的时间量。

因此，例如对于以下数据

1   2008-01-01 00:00:00.000 120 broken  
1   2008-01-02 00:00:00.000 120 off     
1   2008-01-03 00:00:00.000 240 burning 
1   2008-01-04 00:00:00.000 60  off     
1   2008-01-05 00:00:00.000 60  off     
2   2008-01-01 00:00:00.000 60  broken  
2   2008-01-02 00:00:00.000 30  off     
2   2008-01-03 00:00:00.000 20  burning 
2   2008-01-04 00:00:00.000 600 off     
3   2007-01-04 00:00:00.000 600 off     
4   2007-12-12 00:00:00.000 999999999   onfire

提供范围。

select  @start = dateadd(second, 60, '2008-01-01'), 
@fin = dateadd(second, 60, '2008-01-04')

我想返回结果：

1   broken      60
1   burning     240
1   off         180
1   unknown     258720
2   burning     20
2   off         90
2   unknown     259090
4   onfire      259200

这个问题有点相关：Combining split date range in a SQL query

4

1 回答 1

3

这是迄今为止我想出的最好的：

declare @start datetime
declare @fin datetime 

select  @start = dateadd(second, 60, '2008-01-01'), @fin = dateadd(second, 60, '2008-01-04')

select ServerId, State, Total = sum(
    case when StartTime > @start and DateAdd(second, Seconds, StartTime) <= @fin
        then Seconds
    when StartTime < @start and DateAdd(second, Seconds, StartTime) <= @fin
        then DateDiff(second, @start, DateAdd(second, Seconds, StartTime)) 
    when StartTime < @start and DateAdd(second, Seconds, StartTime) >= @fin
        then DateDiff(second, @start, @fin)
    else 
        DateDiff(second,StartTime,@fin)
    end)
into #t
from ServerStatus 
where @start < dateadd(second, Seconds, StartTime) 
and @fin > StartTime
group by ServerId, State

insert #t
select ServerId, 'unknown', DateDiff(second, @start, @fin) - sum(Total) 
from #t 
group by ServerId
having DateDiff(second, @start, @fin) > sum(Total)

select * from #t 
order by ServerId, State
于 2008-10-08T06:25:56.237 回答