php - 如何转换为 JSON

Question

我很难将这个 PHP 解析为 JSON，有人帮我解决这个问题，我如何将这个 PHP 转换为 JSON

$query = "SELECT SUM(total)  FROM account";
$result = mysql_query($query);

while($row = mysql_fetch_assoc($result))
{
echo $row['SUM(total)'];
}

Answer 1

试试json_encode喜欢

$query = "SELECT SUM(total) as total  FROM account";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result))
{
    $new_arr[] = $row['total'];
}
echo json_encode($new_arr);

尽量避免使用mysql_*函数，因为它们已被弃用。而是使用mysqli_*函数或PDO语句。

Answer 2

$query = "SELECT SUM(total) as t  FROM account";
$result = mysql_query($query);

while($row = mysql_fetch_assoc($result))
{
    $new_arr[] = $row['t'];
}
echo json_encode($new_arr);

Answer 3

json_encode()在php中使用函数。

检查参考here

while($row = mysql_fetch_assoc($result))
{
    $myArray[] = $row['SUM(total)'];
}
echo json_encode($myArray);

Answer 4

while($row = mysql_fetch_assoc($result))
{
    $new_arr[] = array("total"=>$row['SUM(total)']);
}
echo json_encode($new_arr);