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所以我正在尝试构建一个脚本来计算给定邮政编码与其他邮政编码列表之间的距离，检查哪个是最小的。我一直在使用 document.write("") 作为调试工具来检查事物的值。问题是，在离开回调函数的范围后，似乎没有变量保留它们的值。例如，如果我使用地理编码器回调函数为 miledistance 变量调用 document.write，它会给我一个正确的答案。如果在将距离值存储在距离数组中的 fillarray 函数中调用 document.write，这甚至是正确的。但是，如果我在回调函数之外检查某个数组的值，例如在 showLocations 函数的末尾，则该数组将显示为未定义。

这是我的第一个 stackoverflow 问题，因此对于回答此问题时的任何失礼，我提前道歉。

 <head>
 <meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
 <title>Google Maps JavaScript API Example: Extraction of Geocoding Data</title>
 <script src="http://maps.google.com/maps?file=api&v=2&key=AIzaSyC8BdiVC-BCDF6zFhzR47dRc7gAryotnM0" type="text/javascript"></script>
 <!-- According to the Google Maps API Terms of Service you are required display a Google map when using the Google Maps API. see: http://code.google.com/apis/maps/terms.html -->
 <script type="text/javascript">
 <cfoutput query = "getAddress">
var #toScript(zip,"zip")#;
 </cfoutput>// Some coldfusion that creates the single zipcode from somewhere else

var geocoder, 

function initialize() {
    geocoder = new GClientGeocoder();
}

var miledistance;
var distances = new Array();
function showLocation() {
    var chapters = new Array();

    chapters[0] = "62650";
    chapters[1] = "44323";
    chapters[2] = "55555";
    chapters[3] = "23624";
    chapters[4] = "86753";
    var closest = "10,000.0";

geocoder.getLatLng(zip,function(point){

        for(var i= 0;i<5;i++){
            if(point !==null){
                var res= point;
                geocoder.getLatLng(chapters[i],function(point){
                miledistance = point.distanceFrom(res,3959);
                fillarray(i, miledistance);

                });


            }else{
                document.write("Address not Processed");
            }
        }
        });
    document.write(distance[0]);
}
function fillarray(i, distance){

    distances[i] = distance;


}
function calculateDistance()
{
    try
    {
        var glatlng1 = new GLatLng(location1.lat, location1.lon);
        var glatlng2 = new GLatLng(location2.lat, location2.lon);
        var miledistance = glatlng1.distanceFrom(glatlng2, 3959).toFixed(1);
        var kmdistance = (miledistance * 1.609344).toFixed(1);

        document.getElementById('results').innerHTML = '<strong>Address 1: </strong>' + location1.address + '<br /><strong>Address 2: </strong>' + location2.address + '<br /><strong>Distance: </strong>' + miledistance + ' miles (or ' + kmdistance + ' kilometers)';
        return miledistance;
    }
    catch (error)
    {
        alert(error);
    }

}

</script>
</head>
4

1 回答 1

1

那个怎么样？

http://maps.googleapis.com/maps/api/distancematrix/xml?origins=NEW-YORK-10001&destinations=WASHINGTON+20001&sensor=false

结果：

<DistanceMatrixResponse>
  <status>OK</status>
  <origin_address>New York, NY 10001, USA</origin_address>
  <destination_address>Washington, DC 20001, USA</destination_address>
  <row>
    <element>
      <status>OK</status>
      <duration>
        <value>13082</value>
        <text>3 hours 38 mins</text>
      </duration>
      <distance>
        <value>364365</value>
        <text>364 km</text>
      </distance>
    </element>
  </row>
</DistanceMatrixResponse>

资料来源：如何在谷歌地图 API 上按城市 + 邮政编码获取距离

于 2013-08-08T22:07:33.317 回答