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I implemented a standalone server with the help of this tutorial:
http://www.tutorialspoint.com/ruby/ruby_web_services.htm

The code is :

require "soap/rpc/standaloneserver"

begin
   class MyServer < SOAP::RPC::StandaloneServer

      # Expose our services
      def initialize(*args)
        super(args[0], args[1], args[2], args[3])
         add_method(self, 'add', 'a', 'b')
         add_method(self, 'div', 'a', 'b')
      end

      # Handler methods
      def add(a, b)
         return a + b
      end
      def div(a, b)
         return a / b
      end
  end
  server = MyServer.new("soapservice", 'soapservice', 'localhost', 8080)

  trap('INT'){server.shutdown  }
  server.start
rescue => err
  puts err.message
end

当我尝试通过指向 localhost:8080 从浏览器访问它时,它给了我以下错误“[2013-08-08T16:31:19.040360 #4840] 错误——soapservice: GET request not allowed”。我尝试通过 POST 访问它,但仍然是同样的问题。谁能告诉我应该使用什么正确的 URL 来使用此 Web 服务?

4

1 回答 1

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尝试将此添加到顶部

require 'rubygems'
#gem 'soap4r'
gem 'soap4r-ruby1.9'
require 'soap/rpc/standaloneServer'
require 'builder'
于 2013-09-24T07:08:04.403 回答