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我有一个带有 ID 和责任经理的项目表。责任经理列的值与John,Jim项目 1 和Jim,Julie项目 2 相同。

但是如果我将 Jim 传递给我的存储过程,我应该得到 2 个项目 (1,2)。这不会返回任何行,因为该列是John,Jim但 SQL Server 正在寻找='Jim'

 select distinct ID,Manager from Projects where Manager=@Manager
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4 回答 4

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WHERE ',' + Manager + ',' LIKE '%,Jim,%'

或者我想匹配你的实际代码:

WHERE ',' + Manager + ',' LIKE '%,' + @Manager + ',%'

请注意,您的设计存在极大缺陷。根本没有理由将名称存储在此表中,更不用说任何数据点的逗号分隔列表。这些事实本身很重要,所以要这样对待它们!

CREATE TABLE dbo.Managers
(
  ManagerID INT PRIMARY KEY,
  Name NVARCHAR(64) NOT NULL UNIQUE, ...
);

CREATE TABLE dbo.Projects
(
  ProjectID INT PRIMARY KEY,
  Name NVARCHAR(64) NOT NULL UNIQUE, ...
);

CREATE TABLE dbo.ProjectManagers
(
  ProjectID INT NOT NULL FOREIGN KEY REFERENCES dbo.Projects(ProjectID),
  ManagerID INT NOT NULL FOREIGN KEY REFERENCES dbo.Managers(ManagerID)
);

现在设置您提到的示例数据:

INSERT dbo.Managers(ManagerID, Name)
  VALUES(1,N'John'),(2,N'Jim'),(3,N'Julie');

INSERT dbo.Projects(ProjectID, Name)
  VALUES(1,N'Project 1'),(2,N'Project 2');

INSERT dbo.ProjectManagers(ProjectID,ManagerID)
  VALUES(1,1),(1,2),(2,2),(2,3);

现在查找 Jim 管理的所有项目:

DECLARE @Manager NVARCHAR(32) = N'Jim';

SELECT p.ProjectID, p.Name
  FROM dbo.Projects AS p
  INNER JOIN dbo.ProjectManagers AS pm
  ON p.ProjectID = pm.ProjectID
  INNER JOIN dbo.Managers AS m
  ON pm.ManagerID = m.ManagerID
  WHERE m.name = @Manager;

或者你甚至可以手动短路一下:

DECLARE @Manager NVARCHAR(32) = N'Jim';


DECLARE @ManagerID INT;
SELECT @ManagerID = ManagerID
  FROM dbo.Managers
  WHERE Name = @Manager;

SELECT p.ProjectID, p.Name
  FROM dbo.Projects AS p
  INNER JOIN dbo.ProjectManagers AS pm
  ON p.ProjectID = pm.ProjectID
  WHERE pm.ManagerID = @ManagerID;

甚至更多:

DECLARE @Manager NVARCHAR(32) = N'Jim';


DECLARE @ManagerID INT;
SELECT @ManagerID = ManagerID
  FROM dbo.Managers
  WHERE Name = @Manager;

SELECT ProjectID, Name
  FROM dbo.Projects AS p
  WHERE EXISTS 
  (
    SELECT 1 
      FROM dbo.ProjectManagers AS pm
      WHERE pm.ProjectID = p.ProjectID
      AND pm.ManagerID = @ManagerID
  );

顺便说一句,我真的,真的,真的希望DISTINCT您原始查询中的 是不必要的。你真的有不止一个同名同ID的项目

于 2013-08-08T21:10:54.130 回答
0

WHERE子句中,=运算符会查找完全匹配的内容。您可以使用LIKE带有通配符的 a 进行部分匹配。

where Manager LIKE '%Jim%'
于 2013-08-08T21:09:39.733 回答
0

您可以尝试以下方法:

SELECT DISTINCT 
    ID,
    Manager 
FROM 
    Projects 
WHERE 
    (
     (Manager LIKE @Manager + ',*') OR
     (Manager LIKE '*,' + @Manager) OR
     (Manager  = @Manager) 
    )

这应该涵盖姓名和姓氏,同时仍在搜索文字值。然而,性能可能是一个问题,具体取决于表

于 2013-08-08T22:16:11.420 回答
0

请尝试以下查询

select distinct ID,Manager from Projects where replace('#$#' + Manager + '#$#', ',', '#$#') like '%Jim%'
于 2013-08-09T09:26:17.040 回答