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我正在编写一个 Android 测验应用程序。我想从 XML 文件加载问题，将它们放入字符串中，然后将这些字符串用作按钮文本。

我在使用 XML 解析时遇到问题。我使用XmlPullParserFactory和XmlPullParser。我什XMLResourceParser至尝试过，但没有成功。我怎样才能正确地做到这一点？

这是 OnCreate 中的初始化：

XmlPullParserFactory pullParserFactory;
    try {
        pullParserFactory = XmlPullParserFactory.newInstance();
        XmlPullParser parser = pullParserFactory.newPullParser();
        InputStream in_s = getApplicationContext().getAssets().open("new_anwers.xml");
        parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
        parser.setInput(in_s, null);
        loadAnswers(parser);
    } catch (XmlPullParserException e) {
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

这些是函数和辅助类：

void loadAnswers(XmlPullParser parser) throws XmlPullParserException,IOException
{
    ArrayList<Answer> answers = null;
    int eventType = parser.getEventType();
    Answer currAnswer = null;

    while (eventType != XmlPullParser.END_DOCUMENT) {
        String name = null;

        switch(eventType){
        case XmlPullParser.START_DOCUMENT:
            answers = new ArrayList();
            break;
        case XmlPullParser.START_TAG:
            name = parser.getName();
            if(name == "answer1") {
                currAnswer = new Answer();                  
            } else if (currAnswer != null) {
                if(name == "text1") {
                    currAnswer.text1 = parser.nextText();
                } else if(name == "text2") {
                    currAnswer.text2 = parser.nextText();
                } else if(name == "text3") {
                    currAnswer.text3 = parser.nextText();
                } else if(name == "text4") {
                    currAnswer.text4 = parser.nextText();
                }
            }
            break;
        case XmlPullParser.END_TAG:
            name = parser.getName();
            if (name.equalsIgnoreCase("answer1") && currAnswer!= null){
                answers.add(currAnswer);
            }
        }
        eventType = parser.next();
    }
    setBtnTxt(answers);
}

class Answer {
    String text1;
    String text2;
    String text3;
    String text4;
}

void setBtnTxt(ArrayList<Answer> answers) {     
    String[] txt = new String[4];
    Iterator<Answer> it = answers.iterator();
    while(it.hasNext())
    {
        Answer currAnswer = it.next();
        txt[1] = currAnswer.text1;
        txt[2] = currAnswer.text2;
        txt[3] = currAnswer.text3;
        txt[4] = currAnswer.text4;
    }

    Button odgA = (Button) findViewById(R.id.button_OdgA);
    Button odgB = (Button) findViewById(R.id.button_OdgB);
    Button odgC = (Button) findViewById(R.id.button_OdgC);
    Button odgD = (Button) findViewById(R.id.button_OdgD);      

    odgA.setText(txt[1]);
    odgB.setText(txt[2]);
    odgC.setText(txt[3]);
    odgD.setText(txt[4]);
}

这是答案 XML：

<?xml version="1.0" encoding="UTF-8"?>
<new_answers>
<answer1>
    <text1>Zvonimir</text1>
    <text2>Tomislav</text2>
    <text3>Branimir</text3>
    <text4>Viseslav</text4>
</answer1>
<answer2>
    <text1>Stipe Mesic</text1>
    <text2>Ivo Josipovic</text2>
    <text3>Franjo Tuđman</text3>
    <text4>Mate Granic</text4>
</answer2>
<answer3>
    <text1>Hrvatski politicar</text1>
    <text2>Hrvatski akademik</text2>
    <text3>Hrvatski glazbenik</text3>
    <text4>Hrvatski branitelj</text4>
</answer3>
</new_answers>
4

1 回答 1

1

How can I correctly accomplish this?

This is not directly related to your question of XML parsing, but you can save yourselves the trouble of parsing XML if you can convert your answers xml to a string array format and put them inside res/values/arrays.xml. In the code you can access them using R.array.<answer_name_id>

For example,

<answer1>
    <text1>Zvonimir</text1>
    <text2>Tomislav</text2>
    <text3>Branimir</text3>
    <text4>Viseslav</text4>
</answer1>

will be

<string-array name="answer_1">
        <item>Zvonimir</item>
        <item>Tomislav</item>
        <item>Branimir</item>
        <item>Viseslav</item>
</string-array>

In code, you can simply access the array as

String[] options = getResources().getStringArray(R.array.answer_1);

Since you have many arrays, you can define an int array to hold references to all your arrays.

public static final int[] ALL_ANSWERS = {
        R.array.answer_1,
        R.array.answer_2,
        R.array.answer_3,
        R.array.answer_4,
        R.array.answer_5}

And in code you can simply loop or access your required answer from

String[] options = getResources().getStringArray(ALL_ANSWERS[index]);

However, if you are downloading the XML from some where else, this won't work. This works only if all your answers are packaged in the app.

于 2013-08-08T15:41:13.883 回答