3

这是我当前的代码(我觉得问题出在我的codeAddress函数中):

<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false"></script>`
<script>
    var geocoder;
    var map;
    function initialize() {
    geocoder = new google.maps.Geocoder();
    var latlng = new google.maps.LatLng(-34.397, 150.644);
    var mapOptions = {
        zoom: 8,
        center: latlng,
        mapTypeId: google.maps.MapTypeId.ROADMAP
    }
    map = new google.maps.Map(document.getElementById("map-canvas"), mapOptions);
    }

    function codeAddress() {
    var address = document.getElementById("address").text;
    geocoder.geocode( { 'address': address}, function(results, status) {
        if (status == google.maps.GeocoderStatus.OK) {
        map.setCenter(results[0].geometry.location);
        var marker = new google.maps.Marker({
            map: map,
            position: results[0].geometry.location
        });
        } else {
        alert("Geocode was not successful for the following reason: " + status);
        }
    });
    }

    google.maps.event.addDomListener(window, 'load', codeAddress);
    google.maps.event.addDomListener(window, 'load', initialize);
</script>
<div id="map-canvas" style="width: 100%; height: 320px;" ></div>
<div id="address">92867</div>

我想要做的是当页面加载时,地址将通过 PHP 填充。我希望 codeAddress 使用填充的地址运行。如何调整此脚本以将其替换var latlng = new google.maps.LatLng(-34.397, 150.644);为我指定地址的正确代码。

4

1 回答 1

3
  1. 消除
    google.maps.event.addDomListener(window, 'load', codeAddress);
    并添加:
    代码地址()
    到最后initialize(),保证map已经创建,什么时候codeAddress();会执行

  2. 替换这一行:
    var address = document.getElementById("address").text;
    通过该行:
    var address = document.getElementById("address").firstChild.data;
    <div/> 没有文本属性
于 2013-08-08T15:07:03.747 回答