4

我正在滚动一个Coroutine用于教育目的的包，这里是：

data Step a b r 
  = Stop
  | Yield b r      
  | Await (a -> r) 

instance Functor (Step a b) where
   fmap g s = case s of 
   Stop       -> Stop
   Yield b r  -> Yield b $ g r
   Await f    -> Await (g . f) 

data CoroutineT m a b = CoT { resume :: m (Step a b (CoroutineT m a b)) }

run_ :: Monad m => CoroutineT m a b -> [a] -> m [b]
run_ (CoT m) as = m >>= \step -> case step of
     Stop      -> return []
     Yield o r -> liftM (o:) $ run_ r as 
     Await k   -> case is of 
       []     -> return [] 
       (x:xs) -> run_ (k x) xs

instance Monad m => Functor (CoroutineT m a) where
  fmap g (CoT m) = CoT $ liftM ap m where 
    ap Stop        = Stop
    ap (Yield b r) = Yield (g b) (fmap g r)
    ap (Await k)   = Await $ (fmap g) . k


instance Monad m => Monad (CoroutineT m a) where
   return b      = CoT . return . Yield b $ return b    
   (CoT m) >>= g = CoT $ liftM go m where 
        go Stop        = Stop
        go (Yield b r) = undefined      -- * This line I am having trouble with
        go (Await k)   = Await $ (>>=g) . k

正如您在上面的评论中看到的那样，我唯一遇到的问题是Yield，我可以看到

(>>=)     :: CoroutineT m a b -> (b -> CoroutineT m a c) -> CoroutineT m a c
(g b)     :: CoroutineT m a c
r         :: CoroutineT m a b
(r >>= g) :: CoroutineT m a c

但我不确定

  1. 如何将它们放在一起以便进行类型检查
  2. bind在这种情况下的语义是什么Yield
4

2 回答 2

4

基础函子应该是：

data Step a b r x 
  = Stop r
  | Yield b x      
  | Await (a -> x)

...你的协程类型应该是：

data CoroutineT m a b r = CoT { resume :: m (Step a b r (CoroutineT m a b r)) }

除非您进行这两个修复，否则它将无法正常工作。

于 2013-08-08T14:51:46.440 回答
3

根据 Gabriel 的建议，替代实施。

data Step a b x r 
  = Done x 
  | Yield b r
  | Await (a -> r)
  | Fail

instance Functor (Step a b x) where
    fmap g s = case s of 
        Done x    -> Done x
        Yield b r -> Yield b (g r)
        Await k   -> Await $ g . k
        Fail      -> Fail


-- | note the monad type needs to parameterize over type of `x` in `Done x`
data CoroutineT a b m x = CoT { resume :: m (Step a b x (CoroutineT a b m x)) }

instance Monad m => Functor (CoroutineT a b m) where
  fmap g (CoT m) = CoT $ liftM ap m where 
    ap (Done x)    = Done $ g x
    ap (Yield b r) = Yield b (fmap g r) 
    ap (Await k)   = Await $ (fmap g) . k
    ap Fail        = Fail


instance Monad m => Monad (CoroutineT a b m) where
  return = CoT . return . Done
  (CoT m) >>= g = CoT $ m >>= \step -> case step of 
    Done x    -> resume $ g x
    Yield b r -> return . Yield b $ r >>= g
    Await k   -> return . Await $ (>>=g) . k   
    Fail      -> return Fail

请注意，return现在的实现也更有意义。

于 2013-08-08T17:29:34.293 回答