承诺
const { promises: { readdir } } = require('fs')
const getDirectories = async source =>
(await readdir(source, { withFileTypes: true }))
.filter(dirent => dirent.isDirectory())
.map(dirent => dirent.name)
打回来
const { readdir } = require('fs')
const getDirectories = (source, callback) =>
readdir(source, { withFileTypes: true }, (err, files) => {
if (err) {
callback(err)
} else {
callback(
files
.filter(dirent => dirent.isDirectory())
.map(dirent => dirent.name)
)
}
})
同步返回
const { readdirSync } = require('fs')
const getDirectories = source =>
readdirSync(source, { withFileTypes: true })
.filter(dirent => dirent.isDirectory())
.map(dirent => dirent.name)
使用路径列出目录。
function getDirectories(path) {
return fs.readdirSync(path).filter(function (file) {
return fs.statSync(path+'/'+file).isDirectory();
});
}
我来这里是为了寻找一种获取所有子目录及其所有子目录等的方法。在接受的答案的基础上，我写了这个：
const fs = require('fs');
const path = require('path');
function flatten(lists) {
return lists.reduce((a, b) => a.concat(b), []);
}
function getDirectories(srcpath) {
return fs.readdirSync(srcpath)
.map(file => path.join(srcpath, file))
.filter(path => fs.statSync(path).isDirectory());
}
function getDirectoriesRecursive(srcpath) {
return [srcpath, ...flatten(getDirectories(srcpath).map(getDirectoriesRecursive))];
}
这应该这样做：
CoffeeScript（同步）
fs = require 'fs'
getDirs = (rootDir) ->
files = fs.readdirSync(rootDir)
dirs = []
for file in files
if file[0] != '.'
filePath = "#{rootDir}/#{file}"
stat = fs.statSync(filePath)
if stat.isDirectory()
dirs.push(file)
return dirs
CoffeeScript（异步）
fs = require 'fs'
getDirs = (rootDir, cb) ->
fs.readdir rootDir, (err, files) ->
dirs = []
for file, index in files
if file[0] != '.'
filePath = "#{rootDir}/#{file}"
fs.stat filePath, (err, stat) ->
if stat.isDirectory()
dirs.push(file)
if files.length == (index + 1)
cb(dirs)
JavaScript（异步）
var fs = require('fs');
var getDirs = function(rootDir, cb) {
fs.readdir(rootDir, function(err, files) {
var dirs = [];
for (var index = 0; index < files.length; ++index) {
var file = files[index];
if (file[0] !== '.') {
var filePath = rootDir + '/' + file;
fs.stat(filePath, function(err, stat) {
if (stat.isDirectory()) {
dirs.push(this.file);
}
if (files.length === (this.index + 1)) {
return cb(dirs);
}
}.bind({index: index, file: file}));
}
}
});
}
或者，如果您能够使用外部库，则可以使用filehound. 它支持回调、承诺和同步调用。
使用承诺：
const Filehound = require('filehound');
Filehound.create()
.path("MyFolder")
.directory() // only search for directories
.find()
.then((subdirectories) => {
console.log(subdirectories);
});
使用回调：
const Filehound = require('filehound');
Filehound.create()
.path("MyFolder")
.directory()
.find((err, subdirectories) => {
if (err) return console.error(err);
console.log(subdirectories);
});
同步调用：
const Filehound = require('filehound');
const subdirectories = Filehound.create()
.path("MyFolder")
.directory()
.findSync();
console.log(subdirectories);
有关更多信息（和示例），请查看文档：https ://github.com/nspragg/filehound
免责声明：我是作者。
对于 node.js 版本 >= v10.13.0，如果选项设置为.fs.readdirSync将返回一个fs.Dirent对象数组。withFileTypestrue
所以你可以使用，
const fs = require('fs')
const directories = source => fs.readdirSync(source, {
withFileTypes: true
}).reduce((a, c) => {
c.isDirectory() && a.push(c.name)
return a
}, [])
var getDirectories = (rootdir , cb) => {
fs.readdir(rootdir, (err, files) => {
if(err) throw err ;
var dirs = files.map(filename => path.join(rootdir,filename)).filter( pathname => fs.statSync(pathname).isDirectory());
return cb(dirs);
})
}
getDirectories( myDirectories => console.log(myDirectories));``
使用 fs-extra，它承诺异步 fs 调用，以及新的 await async 语法：
const fs = require("fs-extra");
async function getDirectories(path){
let filesAndDirectories = await fs.readdir(path);
let directories = [];
await Promise.all(
filesAndDirectories.map(name =>{
return fs.stat(path + name)
.then(stat =>{
if(stat.isDirectory()) directories.push(name)
})
})
);
return directories;
}
let directories = await getDirectories("/")
和 getDirectories 的异步版本，您需要async 模块：
var fs = require('fs');
var path = require('path');
var async = require('async'); // https://github.com/caolan/async
// Original function
function getDirsSync(srcpath) {
return fs.readdirSync(srcpath).filter(function(file) {
return fs.statSync(path.join(srcpath, file)).isDirectory();
});
}
function getDirs(srcpath, cb) {
fs.readdir(srcpath, function (err, files) {
if(err) {
console.error(err);
return cb([]);
}
var iterator = function (file, cb) {
fs.stat(path.join(srcpath, file), function (err, stats) {
if(err) {
console.error(err);
return cb(false);
}
cb(stats.isDirectory());
})
}
async.filter(files, iterator, cb);
});
}
这个答案不使用像readdirSyncor之类的阻塞函数statSync。它不使用外部依赖，也不会陷入回调地狱的深处。
相反，我们使用现代 JavaScript 便利，如 Promises 和 andasync-await语法。并且异步结果是并行处理的；不是顺序的-
const { readdir, stat } =
require ("fs") .promises
const { join } =
require ("path")
const dirs = async (path = ".") =>
(await stat (path)) .isDirectory ()
? Promise
.all
( (await readdir (path))
.map (p => dirs (join (path, p)))
)
.then
( results =>
[] .concat (path, ...results)
)
: []
我将安装一个示例包，然后测试我们的功能 -
$ npm install ramda
$ node
让我们看看它的工作 -
> dirs (".") .then (console.log, console.error)
[ '.'
, 'node_modules'
, 'node_modules/ramda'
, 'node_modules/ramda/dist'
, 'node_modules/ramda/es'
, 'node_modules/ramda/es/internal'
, 'node_modules/ramda/src'
, 'node_modules/ramda/src/internal'
]
使用广义模块 ，Parallel我们可以简化dirs-
const Parallel =
require ("./Parallel")
const dirs = async (path = ".") =>
(await stat (path)) .isDirectory ()
? Parallel (readdir (path))
.flatMap (f => dirs (join (path, f)))
.then (results => [ path, ...results ])
: []
上面使用的Parallel模块是从一组旨在解决类似问题的函数中提取的模式。有关更多说明，请参阅此相关问答。
const {Node} = require("graph-fs");
const directory = new Node("/path/to/directory");
const subDirectories = directory.children.filter(child => child.is.directory);
此答案的 CoffeeScript 版本，具有适当的错误处理：
fs = require "fs"
{join} = require "path"
async = require "async"
get_subdirs = (root, callback)->
fs.readdir root, (err, files)->
return callback err if err
subdirs = []
async.each files,
(file, callback)->
fs.stat join(root, file), (err, stats)->
return callback err if err
subdirs.push file if stats.isDirectory()
callback null
(err)->
return callback err if err
callback null, subdirs
取决于异步
或者，为此使用模块！ （所有东西都有模块。[需要引用]）
如果您需要使用所有async版本。你可以有这样的东西。
记录目录长度，将其用作指示是否所有异步统计任务都已完成。
如果 async stat 任务完成，则所有文件 stat 都已检查，所以调用回调
这仅在 Node.js 是单线程时才有效，因为它假定没有两个异步任务会同时增加计数器。
'use strict';
var fs = require("fs");
var path = require("path");
var basePath = "./";
function result_callback(results) {
results.forEach((obj) => {
console.log("isFile: " + obj.fileName);
console.log("fileName: " + obj.isFile);
});
};
fs.readdir(basePath, (err, files) => {
var results = [];
var total = files.length;
var finished = 0;
files.forEach((fileName) => {
// console.log(fileName);
var fullPath = path.join(basePath, fileName);
fs.stat(fullPath, (err, stat) => {
// this will work because Node.js is single thread
// therefore, the counter will not increment at the same time by two callback
finished++;
if (stat.isFile()) {
results.push({
fileName: fileName,
isFile: stat.isFile()
});
}
if (finished == total) {
result_callback(results);
}
});
});
});
如您所见，这是一种“深度优先”的方法，这可能会导致回调地狱，而且它不是很“实用”。人们试图用 Promise 解决这个问题，方法是将异步任务包装到 Promise 对象中。
'use strict';
var fs = require("fs");
var path = require("path");
var basePath = "./";
function result_callback(results) {
results.forEach((obj) => {
console.log("isFile: " + obj.fileName);
console.log("fileName: " + obj.isFile);
});
};
fs.readdir(basePath, (err, files) => {
var results = [];
var total = files.length;
var finished = 0;
var promises = files.map((fileName) => {
// console.log(fileName);
var fullPath = path.join(basePath, fileName);
return new Promise((resolve, reject) => {
// try to replace fullPath wil "aaa", it will reject
fs.stat(fullPath, (err, stat) => {
if (err) {
reject(err);
return;
}
var obj = {
fileName: fileName,
isFile: stat.isFile()
};
resolve(obj);
});
});
});
Promise.all(promises).then((values) => {
console.log("All the promise resolved");
console.log(values);
console.log("Filter out folder: ");
values
.filter((obj) => obj.isFile)
.forEach((obj) => {
console.log(obj.fileName);
});
}, (reason) => {
console.log("Not all the promise resolved");
console.log(reason);
});
});
使用fs、path模块可以得到文件夹。这个使用 Promise。如果你会得到填充，你可以将isDirectory()更改为isFile() Nodejs--fs--fs.Stats。最后，你可以获得文件'name file'extname 等等Nodejs---Path
var fs = require("fs"),
path = require("path");
//your <MyFolder> path
var p = "MyFolder"
fs.readdir(p, function (err, files) {
if (err) {
throw err;
}
//this can get all folder and file under <MyFolder>
files.map(function (file) {
//return file or folder path, such as **MyFolder/SomeFile.txt**
return path.join(p, file);
}).filter(function (file) {
//use sync judge method. The file will add next files array if the file is directory, or not.
return fs.statSync(file).isDirectory();
}).forEach(function (files) {
//The files is array, so each. files is the folder name. can handle the folder.
console.log("%s", files);
});
});
完全异步的 ES6 版本，只有原生包 fs.promises 和 async/await 并行执行文件操作：
const fs = require('fs');
const path = require('path');
async function listDirectories(rootPath) {
const fileNames = await fs.promises.readdir(rootPath);
const filePaths = fileNames.map(fileName => path.join(rootPath, fileName));
const filePathsAndIsDirectoryFlagsPromises = filePaths.map(async filePath => ({path: filePath, isDirectory: (await fs.promises.stat(filePath)).isDirectory()}))
const filePathsAndIsDirectoryFlags = await Promise.all(filePathsAndIsDirectoryFlagsPromises);
return filePathsAndIsDirectoryFlags.filter(filePathAndIsDirectoryFlag => filePathAndIsDirectoryFlag.isDirectory)
.map(filePathAndIsDirectoryFlag => filePathAndIsDirectoryFlag.path);
}
经测试，效果很好。
以防万一其他人从网络搜索中结束，并且 Grunt 已经在他们的依赖项列表中，这个问题的答案就变得微不足道了。这是我的解决方案：
/**
* Return all the subfolders of this path
* @param {String} parentFolderPath - valid folder path
* @param {String} glob ['/*'] - optional glob so you can do recursive if you want
* @returns {String[]} subfolder paths
*/
getSubfolders = (parentFolderPath, glob = '/*') => {
return grunt.file.expand({filter: 'isDirectory'}, parentFolderPath + glob);
}
感谢 Mayur 了解我withFileTypes。我编写了以下代码以递归方式获取特定文件夹的文件。它可以很容易地修改为只获取目录。
const getFiles = (dir, base = '') => readdirSync(dir, {withFileTypes: true}).reduce((files, file) => {
const filePath = path.join(dir, file.name)
const relativePath = path.join(base, file.name)
if(file.isDirectory()) {
return files.concat(getFiles(filePath, relativePath))
} else if(file.isFile()) {
file.__fullPath = filePath
file.__relateivePath = relativePath
return files.concat(file)
}
}, [])
函数式编程
const fs = require('fs')
const path = require('path')
const R = require('ramda')
const getDirectories = pathName => {
const isDirectory = pathName => fs.lstatSync(pathName).isDirectory()
const mapDirectories = pathName => R.map(name => path.join(pathName, name), fs.readdirSync(pathName))
const filterDirectories = listPaths => R.filter(isDirectory, listPaths)
return {
paths:R.pipe(mapDirectories)(pathName),
pathsFiltered: R.pipe(mapDirectories, filterDirectories)(pathName)
}
}