ruby - 遍历循环访问两个元素（如果存在）

Question

好吧，我还没有找到一个干净的解决方案来轻松地用 Ruby 编写这段代码：

# Java style version:
array.each do |i, el|
  if i < array.length - 1
     process(array[i], array[i+1])
  end
end

# Would be nice if I could do something like this:
array.each do |i, el, next|
  process(el, next)
end

Answer 1

您可以使用each_cons：

array.each_cons(2) do |a, b|
  process(a, b)
end

Answer 2

ar = [1,2,3,4]
(ar.size - 1).times {|i| process ar[i],ar[i+1]}