我有一个为客户维护的 Access 数据库。
我有 4 张桌子。索赔、资格、药房和代码。
我使用的主键是 PHID + SID = MemberID,我链接到每个表,然后代码表仅用于描述。请参阅下面的查询以获得更好的可视化...
查询 1:Member_Claims_Query
SELECT
Eligibility.GROUPID,
Eligibility.PHID & '-' & Eligibility.SID AS MemberID,
[Eligibility].[DOB] AS DOB,
Eligibility.GENDER,
Eligibility.RELATIONSHIP_CODE,
MaxDiagDollars.HighestDiagPaid/SUM(Claims.PAID_AMT) AS ['%'],
MaxDiagDollars.HighestDiagPaid/SUM(Claims.PAID_AMT) as 'Percent',
ROUND(SUM(Claims.PAID_AMT)) AS TOTALPAID,
ROUND(Sum(IIf(Format(Serv_Beg_Date,'yyyy')='2011',Claims.PAID_AMT,0))) AS 2011TOTALPAID,
ROUND(Sum(IIf(Format(Serv_Beg_Date,'yyyy')='2012',Claims.PAID_AMT,0))) AS 2012TOTALPAID,
ROUND(Sum(IIf(Format(Serv_Beg_Date,'yyyy')='2013',Claims.PAID_AMT,0))) AS 2013TOTALPAID
FROM (Claims
INNER JOIN Eligibility
ON (Claims.[SID] = Eligibility.[SID]) AND (Claims.[PHID] = Eligibility.[PHID]))
INNER JOIN (SELECT PHID, SID, MAX(TotalPaid) AS HighestDiagPaid
FROM (SELECT [PHID], [SID], DIAG_CODE1, SUM(PAID_AMT) AS TotalPaid FROM Claims GROUP BY [PHID], [SID], [DIAG_CODE1]) AS [%$##@_Alias] GROUP BY PHID, SID) AS MaxDiagDollars ON ( MaxDiagDollars.[PHID]=Eligibility.[PHID] ) AND ( MaxDiagDollars.[SID] = Eligibility.[SID] )
WHERE Eligibility.DOB < DateAdd( 'y', -2, DATE())
GROUP BY
Eligibility.GROUPID, Eligibility.PHID & '-' & Eligibility.SID, [Eligibility].[DOB], Eligibility.GENDER, Eligibility.RELATIONSHIP_CODE, MaxDiagDollars.HighestDiagPaid
HAVING SUM(Claims.PAID_AMT)>10000 and MaxDiagDollars.HighestDiagPaid/SUM(Claims.PAID_AMT) <= 0.80;
此查询应该获取每个成员支付的总金额并给出总金额 PAid,然后每年爆发。
查询 2:Member_By_Diag
SELECT
Eligibility.PHID & '-' & Eligibility.SID AS MemberID,
Claims.Diag_Code1,
ROUND(Sum(Claims.PAID_AMT)) AS TotalPaid,
ROUND(Sum(IIf(Format(Serv_Beg_Date,'yyyy')='2011',Claims.PAID_AMT,0))) AS 2011TotalPaid,
ROUND(Sum(IIf(Format(Serv_Beg_Date,'yyyy')='2012',Claims.PAID_AMT,0))) AS 2012TotalPaid,
ROUND( Sum(IIf(Format(Serv_Beg_Date,'yyyy')='2013',Claims.PAID_AMT,0))) AS 2013TotalPaid
FROM
(Claims
INNER JOIN Eligibility
ON (Claims.[SID] = Eligibility.[SID]) AND (Claims.[PHID] = Eligibility.[PHID]))
INNER JOIN Pharmacy
ON (Eligibility.SID = Pharmacy.SID) AND (Eligibility.PHID = Pharmacy.PHID)
GROUP BY
Eligibility.PHID & '-' & Eligibility.SID, Claims.Diag_Code1
HAVING count( [Pharmacy].[NDC] ) >4 and count(IIF(Claims.REV_CODE= '450',1,0) ) > 1
ORDER BY Eligibility.PHID & '-' & Eligibility.SID;
第二个查询本质上应该获取每个成员的代码,并通过诊断代码分解他们支付的金额。
查询 3:combined_query
SELECT *
FROM (Member_Claims_Query AS a INNER JOIN Member_by_Diag AS b ON a.MemberID=b.MemberID) INNER JOIN Codes AS c ON c.DxCode = b.Diag_Code1;
ISSUE 我的客户给我发了一封电子邮件,说明 Member_By_Diag 查询中的总支付额有时高于 Member_By_Claim 查询中的总支付额。但是它们的计算方式相同。
我打开数据库并编写了一个简单的查询,以查看在 b.Total_Paid (Member_By_Diag.Total_Paid) 大于 Member_Claims_Query.Total_Paid 时返回了多少记录。
在这种情况下,它返回了 262/1278 条记录。
SELECT * FROM Combined_Query WHERE b_TotalPaid > a_TotalPaid
这张照片准确地描述了我和我的客户所看到的。
如你看到的。a_TotalPaid > b_TotalPaid。但是,如果您查看我的查询,它们是否相同?这是按问题分组吗?还是加入问题?任何帮助将非常感激。