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我正在尝试编辑此“从模板生成”脚本。脚本所做的是基于模板，它将信息从电子表格输入到文档。我喜欢它的工作方式，只是它只是将文档命名为模板的副本，然后是行号。这对于我尝试使用它的目的不是很有效。我的问题是我如何能够执行以下选项之一：

A：让名称基于行中的某个单元格。例如，有一列名为 Claim # and Department。我希望这两个组成每个文档的标题。该文档将是：“{department name} {claim #}”，基于导出的行中该列中的信息。

B：在生成询问我希望文件命名的文档时，请放入一个框。

谢谢您的帮助！

PS：如果需要，我将用于文档名称的列是：E 列然后 D 列。

这是代码：（我没有做这个，我在画廊里找到的。）

function generateDocument(e) {
  var template = DocsList.getFileById(e.parameter.Templates);
  var row = e.parameter.row
  var myDocID = template.makeCopy(template.getName()+" - "+ row).getId();
  var myDoc = DocumentApp.openById(myDocID);
  var copyBody = myDoc.getActiveSection();
  var Sheet = SpreadsheetApp.getActiveSpreadsheet();
  //Browser.msgBox(row);
  var myRow = SpreadsheetApp.getActiveSpreadsheet().getRange(row+":"+row);
  for (var i=1;i<Sheet.getLastColumn()+1;i++){
    var myCell = myRow.getCell(1, i);
    copyBody.replaceText("{"+myCell.getA1Notation().replace(row,"")+"}", myCell.getValue());
  }
  myDoc.saveAndClose();
  //var pdf = DocsList.getFileById(copyId).getAs("application/pdf"); 
  //MailApp.sendEmail(email_address, subject, body, {cc: carbonCopy, name: senderName, htmlBody: body, attachments: pdf}); 

  var app = UiApp.getActiveApplication();
  app.close();
  return app; 
}

function getTemplates() {
  var doc = SpreadsheetApp.getActiveSpreadsheet();
  var app = UiApp.createApplication().setTitle('Generate from template');
  // Create a grid with 3 text boxes and corresponding labels
  var grid = app.createGrid(3, 2);
  grid.setWidget(0, 0, app.createLabel('Template name:'));

  var list = app.createListBox();
  list.setName('Templates');
  grid.setWidget(0, 1, list);
  var docs = DocsList.getFolder("Templates").getFilesByType("document");
  for (var i = 0; i < docs.length; i++) {
    list.addItem(docs[i].getName(),docs[i].getId());
  }
  grid.setWidget(1, 0, app.createLabel('Row:'));
  var row = app.createTextBox().setName('row');
  row.setValue(SpreadsheetApp.getActiveSpreadsheet().getActiveRange().getRow());
  grid.setWidget(1, 1, row);
  // Create a vertical panel..
  var panel = app.createVerticalPanel();

  // ...and add the grid to the panel
  panel.add(grid);

  // Create a button and click handler; pass in the grid object as a callback element and the handler as a click handler
  // Identify the function b as the server click handler

  var button = app.createButton('Submit');
  var handler = app.createServerClickHandler('generateDocument');
  handler.addCallbackElement(grid);
  button.addClickHandler(handler);

  // Add the button to the panel and the panel to the application, then display the application app in the Spreadsheet doc
  panel.add(button);
  app.add(panel);
  doc.show(app);
}

function onOpen() {   
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var menuEntries = [{name: "Generate from template", functionName: "getTemplates"}];  
  ss.addMenu("Template Generator", menuEntries);  
}
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1 回答 1

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makeCopy 方法包括为副本命名的可能性，自动完成会清楚地显示它

在此处输入图像描述 所以在你的代码中你可以这样做：

function generateDocument(e) {
  var template = DocsList.getFileById(e.parameter.Templates);
  var Sheet = SpreadsheetApp.getActiveSpreadsheet();// I moved this line a bit to have Sheet available 
  var row = e.parameter.row
  var myDocID = template.makeCopy(Sheet.getRange('E'+row).getValue()+'-'+Sheet.getRange('D'+row).getValue()).getId();// this is a basic implementation to compose the name with content of column D and E separated by a hyphen... customize it the way you want.
  ...
于 2013-08-07T18:36:13.790 回答