我有以下功能
def best(x):
xx = min(x.split(","), key=lambda x: re.findall("\d+.\d+", x.split()[0]))
source = xx.split()[1][1:-1]
value = re.findall("\d+.\d+", xx.split()[0])[0]
return value,source
非常适合这个
3.4-10.4 (BDB),0.1-15.2 (BDB),0.2-17 (BDB) # working great
但不适用于此
3.4-10.4 (BDB),,0.1-15.2 (BDB),0.2-17 (BDB) # not working
你能请,建议,是什么问题?错误是“列表索引超出范围”