c++ - Is everything cleaned up when using 'goto'?

Question

for (int i = 0 ; i < 10 ; ++i)
{
    for (int j = 0 ; j < 10 ; ++j)
    {
        goto label;
    }
}
label:
// stuff

After goto will the i and j variables get freed? From what I recall goto doesn't unwind the stack or do any cleanup so will it screw something up in this case?

Answer 1

是的，它会被清理干净。因为 C++ 释放了超出范围的变量。