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我的 Google 驱动器上托管了一个 XML 文件。它有一些我的 Android 应用程序运行所需的数据。因此,我决定测试是否可以从文件中获取数据并进行测试SAXParser。但是,我得到一个SAXParseException

org.xml.sax.SAXParseException; lineNumber: 1; columnNumber: 1; Premature end of file.
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.fatalError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.reportFatalError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl.parse(Unknown Source)
    at testing.TestSAX.processFeed(TestSAX.java:54)
    at testing.TestSAX.main(TestSAX.java:40)  

虽然同样的代码可以正常工作,比如 RSS 提要,但它会在 Google 驱动器文件中崩溃。
这是我打开流的方式:

try{
            SAXParserFactory factory = SAXParserFactory.newInstance();
            SAXParser parser = factory.newSAXParser();

            InputStream stream = new URL(url).openStream();
            Reader r = new InputStreamReader(stream,"UTF-8");
            InputSource source = new InputSource(stream);
            source.setEncoding("UTF-8");

            parser.parse(source, this);
        }catch(Exception e){
            errorOccured = true;
            e.printStackTrace();
        }  

我该如何解决这个问题?

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1 回答 1

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您的 InputStream 存在问题,请仔细阅读:http://www.danielschneller.com/2008/01/saxparseexception-1-1-premature-end-of.html

于 2013-08-07T08:08:58.013 回答