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我想制作一个 4 块导航菜单，而我已经显示了一个块，然后单击打开第二块，从第二个选择并再次单击出现第三块，第四块也是如此......这是我的代码，如果可以工作会很高兴，但它不是...... :(请提供建议。谢谢！您可以在下面查看代码，或者在下一个链接中查看：http: //jsfiddle.net/9afaF/

<div class="games_content">

            <script>
                $(function() {
                    $("#block_2 div,#block_3 div,#block_4 div").hide();

                    $("#block_1 div").click(function(){
                        $("#block_2 div,#block_3 div,#block_4 div").hide();
                        $("#block_2 div."+$(this).attr('id')).show("fast");

                        $("#block_2 div").click(function(){
                            $("#block_3 div,#block_4 div").hide();
                            $("#block_3 div."+$(this).attr('id')).show("fast");

                            $("#block_3 div").click(function(){
                                $("#block_4 div").hide();
                                $("#block_4 div."+$(this).attr('id')).show("fast");
                            })
                        });
                    });
                });
            </script>
            <div style="float:left;width:237px;height:420px;background: rgba(255, 0, 0, .5);margin-right:15px;" id="block_1">
                <div id="category1">Category 1</div>
                <div id="category2">Category 2</div>
                <div id="category3">Category 3</div>
                <div id="category4">Category 4</div>
                <div id="category5">Category 5</div>
            </div>

            <div style="float:left;width:164px;height:500px;background: rgba(255, 0, 0, .5);margin-right:2px;margin-top:10px;margin-left:4px;" id="block_2">
                <div class="category1" id="subcat1">Sub Category 1</div>
                <div class="category1" id="subcat2">Sub Category 2</div>
                <div class="category1" id="subcat3">Sub Category 3</div>
                <div class="category2" id="subcat4">Sub Category 4</div>
                <div class="category2" id="subcat5">Sub Category 5</div>
                <div class="category3" id="subcat6">Sub Category 6</div>
                <div class="category3" id="subcat7">Sub Category 7</div>
                <div class="category4" id="subcat8">Sub Category 8</div>
                <div class="category4" id="subcat9">Sub Category 9</div>
                <div class="category5" id="subcat10">Sub Category 10</div>
                <div class="category5" id="subcat11">Sub Category 11</div>
            </div>

            <div style="float:left;width:160px;height:500px;background: rgba(255, 0, 0, .5);margin-right:2px;margin-top:10px;" id="block_3">
                <div class="subcat1" id="game1">Sub Sub Categoey 1</div>
                <div class="subcat1" id="game2">Sub Sub Categoey 2</div>
                <div class="subcat2" id="game3">Sub Sub Categoey 3</div>
                <div class="subcat2" id="game4">Sub Sub Categoey 4</div>
                <div class="subcat3" id="game5">Sub Sub Categoey 5</div>
                <div class="subcat4" id="game6">Sub Sub Categoey 6</div>
            </div>

            <div style="float:left;width:240px;height:400px;background: rgba(255, 0, 0, .5);margin-left:17px;" id="block_4">
                <div class="game1">Game1</div>
                <div class="game2">Game2</div>
                <div class="game3">Game3</div>
                <div class="game4">Game4</div>
            </div>

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1 回答 1

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您没有将 jquery 库加载到您的小提琴中。

看到它在这里工作FIDDLE

$(function() {
    $("#block_2 div,#block_3 div,#block_4 div").hide();

    $("#block_1 div").click(function(){
        $("#block_2 div,#block_3 div,#block_4 div").hide();
        $("#block_2 div."+$(this).attr('id')).show("fast");

        $("#block_2 div").click(function(){
            $("#block_3 div,#block_4 div").hide();
            $("#block_3 div."+$(this).attr('id')).show("fast");

            $("#block_3 div").click(function(){
                $("#block_4 div").hide();
                $("#block_4 div."+$(this).attr('id')).show("fast");
            })
        });
    });
});
于 2013-08-07T07:56:51.470 回答