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在问这个问题之前，我已经阅读了关于 stackoverflow 的几个问题。我对php和mysql知之甚少，所以需要很多帮助。

所以，我需要为每个表行创建一个按钮，这样当用户点击“复制”按钮时，该行的数据将被复制到数据库中。我怎样才能做到这一点？

demotable.php (//编辑//)

    <?php 
    require('connect.php');
    $query = "SELECT * FROM trade_history1 ";
    $result = mysql_query($query);
    echo "<table border = '1px'>"; // start a table tag in the HTML
    echo "<tr><td>" . "ID" . "</td><td>" . "Date" . "</td><td>" . "Type" . "</td><td>" . "Size" . "</td><td>" . "Currency Pair" . "</td><td>" . "Entry" . "</td><td>" . "Stoploss" . "</td><td>". "Take Profit" . "</td><td>" . "Date Close" . "</td><td>" ."Close" . "</td><td>" ."Profit/Loss"."</td><td>" ."Copy"."</td></tr>" ;  //$row['index'] the index here is a field name
    while($row = mysql_fetch_array($result)){   //Creates a loop to loop through results
    echo "<tr><td>" . $row['id'] . "</td><td>" . $row['date'] . "</td><td>" . $row['type'] . "</td><td>" . $row['size'] ."</td><td>" . $row['currency_pair'] ."</td><td>" . $row['entry'] ."</td><td>" . $row['stoploss'] ."</td><td>" . $row['takeprofit'] ."</td><td>" . $row['dateclose'] ."</td><td>" . $row['close'] ."</td><td>" . $row['profitloss'] . "</td></tr>";  //$row['index'] the index here is a field name
    }
    echo "</table>"; //Close the table in HTML
    mysql_close(); //Make sure to close out the database connection
    ?>
    <html>
<a href="copytrade.php?id=$_GET['id]"> View </a>
    </html>

复制贸易.php

<?php

        require ('connect.php');

        $mysqli = new mysqli($database_hostname, $database_username, $database_password, $database_name) or exit("Error connecting to database"); 

        $stmt = $mysqli->prepare("INSERT INTO trade_history1 (size, date, type, currency_pair, entry, stoploss, takeprofit, dateclose,close,profitloss) 
                                      SELECT size, date, type, currency_pair, entry, stoploss, takeprofit, dateclose,close,profitloss
                                      FROM trade_history1
                                      WHERE id = ?"); 


        $stmt->bind_param("i", $id); // 


        $successfullyCopied = $stmt->execute(); 


        $stmt->close();

        $mysqli->close();

?>

顺便说一句，每当我单击 demotable.php 上的“复制按钮”时，链接将是：http://localhost/1103242B/demo/copytrade.php?copy=copy. 我可以知道我错过了代码的哪一部分或者我做错了吗？谢谢。

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1 回答 1

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您必须将所有表格设计放在表单标签中。然后对于每一行，您必须添加一个带有 url 之类的复制链接http://localhost/1103242B/demo/copytrade.php?id=id。这里 id 是数据库中的记录 id。您正在生成上面的表格，然后在下面的表格中您没有任何对copytrade.php页面的 id 引用。

这样您也可以这样做，但是在每一行中您可以放置​​一些复选框，然后当用户单击复选框时，将 id 设置在表单内的隐藏字段中，然后您就可以将该 id 发布到copytrade.php.

两种方式都会起作用。

尝试编辑您的页面，如下所示。

<html>
<form method = "GET" action = "copytrade.php">

<?php 
require('connect.php');
$query = "SELECT * FROM trade_history1 "; //You don't need a ; like you do in SQL
$result = mysql_query($query);

echo "<table border = '1px'>"; // start a table tag in the HTML
echo "<tr><td>" . "ID" . "</td><td>" . "Date" . "</td><td>" . "Type" . "</td><td>" . "Size" . "</td><td>" . "Currency Pair" . "</td><td>" . "Entry" . "</td><td>" . "Stoploss" . "</td><td>". "Take Profit" . "</td><td>" . "Date Close" . "</td><td>" ."Close" . "</td><td>" ."Profit/Loss"."</td><td>" ."Copy"."</td><td>Copy</td></tr>" ;  //$row['index'] the index here is a field name

while($row = mysql_fetch_array($result)){   //Creates a loop to loop through results
echo "<tr><td>" . $row['id'] . "</td><td>" . $row['date'] . "</td><td>" . $row['type'] . "</td><td>" . $row['size'] ."</td><td>" . $row['currency_pair'] ."</td><td>" . $row['entry'] ."</td><td>" . $row['stoploss'] ."</td><td>" . $row['takeprofit'] ."</td><td>" . $row['dateclose'] ."</td><td>" . $row['close'] ."</td><td>" . $row['profitloss'] . "</td><td>a href='copytrade.php?id=" .$row['id'].'">copy</a></td></tr>";  //$row['index'] the index here is a field name
}

echo "</table>"; //Close the table in HTML

mysql_close(); //Make sure to close out the database connection
?>

<input type = "submit" name = "copy" value = "copy"/></form>
</html>
于 2013-08-06T18:20:18.470 回答