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undefined index当我尝试screen_name从 Twitter API 1.1 用户时间线访问键值对时出现以下错误https://api.twitter.com/1.1/statuses/user_timeline.json

遇到 PHP 错误

严重性：通知

消息：未定义索引：screen_name

文件名：控制器/search.php

行号：98

当我 print_r(); 时我可以看到 screen_name 键 存储结果的关联数组：

Array ( [0] => Array ( [created_at] => Tue Mar 19 21:55:31 +0000 2013 [id] => 3.141330578148E+17 [id_str] => 314133057814798336 [text] => 赢得 4 件装3 月 26 日至 31 日通过@604Now 获得@VanAutoShow 门票 - http://t.co/2G0pyNNgLl RT 进入！[来源] => Mac 版 Twitter [截断] => [in_reply_to_status_id] => [in_reply_to_status_id_str] => [in_reply_to_user_id] => [in_reply_to_user_id_str] => [in_reply_to_screen_name] => [user] => 数组（[id] => 128700677 [id_str] => 128700677 [name] => Bernard Poon [screen_name] => StackOverflow [location] => 温哥华，不列颠哥伦比亚省 [描述] => 称温哥华为家的 Code Monkey。喜欢 Apple 产品和新手摄影师。[url] => http://t.co/wlxhr5tpes[实体] => 数组 ( [url] => 数组 ( [urls] => 数组 ( [0] => 数组 ( [url] => http://t.co/wlxhr5tpes [expanded_url] => http:// /ceciliaandbernard.com [display_url] => ceciliaandbernard.com [indices] => 数组 ( [0] => 0 1 => 22 ) ) ) ) [description] => 数组 ( [urls] => 数组 ( ) ) ) [受保护] => [followers_count] => 157 [friends_count] => 13 [listed_count] => 4 [created_at] => Thu Apr 01 23:16:57 +0000 2010 [favourites_count] => 0 [utc_offset] =>

如果我使用Users Show TWitter API 1.1 资源且没有错误，我可以访问 screen_name 键值对。但是，当我使用User Timeline Twitter API 1.1 资源时，我收到了上述undefined index错误。下面是我用来访问这两种资源的函数的代码片段，结果不同：

function does_user_exist($r) 
{
    // convert to associative array
    // inorder to search for keys
    $a = json_decode($r, true);         

    echo "Screen Name: " . $a['screen_name'];       
}

任何帮助将不胜感激。提前致谢。

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1 回答 1

3

它在另一个数组中。试试下面的代码

echo "Screen Name: " . $a[0]['screen_name'];
于 2013-08-06T15:06:27.043 回答