php - 如何使用变量从对象的字段中获取数据？

Question

Fe 我有对象 $game，有 3 个截图 $game->screen1, $game->screen2, $game->screen3

我需要得到这样的数据 $game['screen'.$num]，但是在 Object.

Answer 1

你可以这样做：

$game->screen2 = 'this is screen2';
$num = 2;
echo $game->{'screen' . $num}; // "this is screen2"

$game->screen3 = 'this is screen3';
$num = 3;
echo $game->{'screen' . $num}; // "this is screen3"

Answer 2

您可以为此使用数组：

$game->screen = array($screen1, $screen2, $screen3);

$game->screen[$num];