0

就我而言，我有来自多个表的数据，我想提取一个查询。这是关于足球数据的。在一分钟的表格中记录了比赛的日期以及其他记录的数据和比赛结果。问题是我想限制日期的应用，而不是比赛的数量，因为一天有几场比赛。设法构建了一个复杂的查询来显示我的所有数据，但它显示的结果是游戏数量而不是日期，所以我不能使用限制，因为在这种情况下吃东西会变成更多游戏而不是日期。我的问题是是否可以构建一个对日期有限制的应用程序，同时显示日期内所有比赛的结果？这是我现在使用的应用程序的代码：

SELECT
            MAIN.id,
            SECTION.type,
            MAIN.date as date_,
            MAIN.prognosis,
            HOME_TEAM.team_name as home_team,
            GUEST_TEAM.team_name as guest_team,
            FIRST_INDEX.index as f_index,
            SECOND_INDEX.index as s_index,
            THIRD_INDEX.index as t_index,
            DATA.home_result,
            DATA.guest_result,
            DATA.coefficient,
            DATA.success,
            MAIN.total_coefficient,
            MAIN.total_success

        FROM ssdt_matches_main as MAIN

        LEFT JOIN ssdt_section_type as SECTION ON (MAIN.type_id = SECTION.id)
        LEFT JOIN ssdt_matches_data as DATA ON (DATA.matches_main_id = MAIN.id )
        LEFT JOIN ssdt_matches_teams as HOME_TEAM ON (HOME_TEAM.id = DATA.home_team_id )
        LEFT JOIN ssdt_matches_teams as GUEST_TEAM ON (GUEST_TEAM.id = DATA.guest_team_id )
        LEFT JOIN ssdt_matches_index as FIRST_INDEX ON (FIRST_INDEX.id = DATA.first_index_id )
        LEFT JOIN ssdt_matches_index as SECOND_INDEX ON (SECOND_INDEX.id = DATA.second_index_id )
        LEFT JOIN ssdt_matches_index as THIRD_INDEX ON (THIRD_INDEX.id = DATA.third_index_id ) 


        WHERE SECTION.type = 'Risk prognosis'


        ORDER BY MAIN.id DESC
4

2 回答 2

1

您想限制where子句中的日期，例如：

where MAIN.date between date('2012-01-01') and date('2012-12-31');

如果您想获取最近 10 天（匹配）的记录，您可以执行以下操作：

select . . .
from . . . join
     (select date
      from ssdt_matches_main md
      group by date
      order by date desc
      limit 10
     ) datel
     on datel.date = MAIN.date

这使用连接来选择日期列表，然后使用连接来进行过滤。

编辑：

你的from条款看起来像：

    FROM ssdt_matches_main as MAIN

    LEFT JOIN ssdt_section_type as SECTION ON (MAIN.type_id = SECTION.id)
    LEFT JOIN ssdt_matches_data as DATA ON (DATA.matches_main_id = MAIN.id )
    LEFT JOIN ssdt_matches_teams as HOME_TEAM ON (HOME_TEAM.id = DATA.home_team_id )
    LEFT JOIN ssdt_matches_teams as GUEST_TEAM ON (GUEST_TEAM.id = DATA.guest_team_id )
    LEFT JOIN ssdt_matches_index as FIRST_INDEX ON (FIRST_INDEX.id = DATA.first_index_id )
    LEFT JOIN ssdt_matches_index as SECOND_INDEX ON (SECOND_INDEX.id = DATA.second_index_id )
    LEFT JOIN ssdt_matches_index as THIRD_INDEX ON (THIRD_INDEX.id = DATA.third_index_id ) 
    join (select date
          from ssdt_matches_main md
          group by date
          order by date desc
          limit 10
         ) datel
         on datel.date = MAIN.date
于 2013-08-06T11:38:56.743 回答
0

我修复了查询。没有你的帮助，我不会这样做。非常感谢！

SELECT
            MAIN.id,
            SECTION.type,
            MAIN.date as date_,
            MAIN.prognosis,
            HOME_TEAM.team_name as home_team,
            GUEST_TEAM.team_name as guest_team,
            FIRST_INDEX.index as f_index,
            SECOND_INDEX.index as s_index,
            THIRD_INDEX.index as t_index,
            DATA.home_result,
            DATA.guest_result,
            DATA.coefficient,
            DATA.success,
            MAIN.total_coefficient,
            MAIN.total_success

        FROM ssdt_matches_main as MAIN

LEFT JOIN ssdt_section_type as SECTION ON (MAIN.type_id = SECTION.id)
LEFT JOIN ssdt_matches_data as DATA ON (DATA.matches_main_id = MAIN.id )
LEFT JOIN ssdt_matches_teams as HOME_TEAM ON (HOME_TEAM.id = DATA.home_team_id )
LEFT JOIN ssdt_matches_teams as GUEST_TEAM ON (GUEST_TEAM.id = DATA.guest_team_id )
LEFT JOIN ssdt_matches_index as FIRST_INDEX ON (FIRST_INDEX.id = DATA.first_index_id )
LEFT JOIN ssdt_matches_index as SECOND_INDEX ON (SECOND_INDEX.id = DATA.second_index_id )
LEFT JOIN ssdt_matches_index as THIRD_INDEX ON (THIRD_INDEX.id = DATA.third_index_id ) 
JOIN (SELECT id
      FROM ssdt_matches_main md
      WHERE type_id = 2
      ORDER BY id DESC
      LIMIT 0,5
     ) datel
     ON datel.id = DATA.matches_main_id


        ORDER BY MAIN.id DESC
于 2013-08-06T21:06:19.723 回答