以上是我的一个数据表的屏幕截图。我正在尝试将此数据转换为以下格式,以便可以将其绑定到我的一个网格。我尝试过 LINQ,但没有成功。请任何人帮助我如何做到这一点。不一定是 LINQ,但我认为使用 LINQ 会更容易
问问题
1366 次
2 回答
0
试试下面
var result = dataSet.Tables["reportColumns"].AsEnumerable().GroupBy(x => x.Field<string>("Object"))
.Select(g => new
{
ColumnName = g.Key,
DefaultColumn = g.FirstOrDefault(p => p.Field<string>("Attribute") == "DefaultColumn").Field<string>("Value"),
Label = g.FirstOrDefault(p => p.Field<string>("Attribute") == "Label").Field<string>("Value"),
Type = g.FirstOrDefault(p => p.Field<string>("Attribute") == "Type").Field<string>("Value"),
Standard = g.FirstOrDefault().Field<int>("Standard")
}).ToList();
于 2013-08-06T10:10:00.313 回答
0
您可以使用我的ToPivotTable扩展:
public static DataTable ToPivotTable<T, TColumn, TRow, TData>(
this IEnumerable<T> source,
Func<T, TColumn> columnSelector,
Expression<Func<T, TRow>> rowSelector,
Func<IEnumerable<T>, TData> dataSelector)
{
DataTable table = new DataTable();
var rowName = ((MemberExpression)rowSelector.Body).Member.Name;
table.Columns.Add(new DataColumn(rowName));
var columns = source.Select(columnSelector).Distinct();
foreach (var column in columns)
table.Columns.Add(new DataColumn(column.ToString()));
var rows = source.GroupBy(rowSelector.Compile())
.Select(rowGroup => new
{
Key = rowGroup.Key,
Values = columns.GroupJoin(
rowGroup,
c => c,
r => columnSelector(r),
(c, columnGroup) => dataSelector(columnGroup))
});
foreach (var row in rows)
{
var dataRow = table.NewRow();
var items = row.Values.Cast<object>().ToList();
items.Insert(0, row.Key);
dataRow.ItemArray = items.ToArray();
table.Rows.Add(dataRow);
}
return table;
}
从源表创建强类型数据:
var data = from r in table.AsEnumerable()
select new {
Object = r.Field<string>("Object"),
Attribute = r.Field<string>("Attribute"),
Value = r.Field<object>("Value")
};
并将它们转换为数据透视表:
var pivotTable = data.ToPivotTable(r => r.Attribute,
r => r.Object,
rows => rows.First().Value);
这将创建具有不同属性值(即 DefaultColumn、Label、Type)作为列的数据透视表,行将是每个对象值的组,并且每个单元格将具有对象组和属性列的相应值属性的值。
或在单个查询中:
var pivotTable = table.AsEnumerable()
.Select(r => new {
Object = r.Field<string>("Object"),
Attribute = r.Field<string>("Attribute"),
Value = r.Field<object>("Value")
})
.ToPivotTable(r => r.Attribute,
r => r.Object,
rows => rows.First().Value);
于 2013-08-06T10:11:04.930 回答