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I have my array unique that is my main array and my array kind. I need to check that only 1 value of kind is present in the array unique. Then if there is more than 1 value of the array kind in unique I need to unset all values but the first one used in the array.

The further i got to achieve this is with the following code but I can not store the indexpath of the found object to do a later comparison. xcode says "bad receiver type nsinteger"

could anyone help me to achieve this?

kind = @[@"#Routine",@"#Exercise",@"#Username"];
    NSMutableArray *uniqueKind = [NSMutableArray array];
    for (NSString* obj in kind) {
        if ( [unique containsObject:obj] ) {
            NSInteger i = [unique indexOfObject:obj];
            [uniqueKind addObject: [i intValue]];
        }
    }
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3 回答 3

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AnNSInteger就像 an int，因此您不能向它发送消息 ( [i intValue])。此外，您不能将 an 添加NSInteger到数组而不使其成为NSNumber或其他对象类型。你可以这样做：

NSInteger i = [unique indexOfObject:obj];
[uniqueKind addObject: [NSNumber numberWithInteger:i]];

此外（不了解您在做什么）您可能想要使用 anNSSet而不是数组。你可以结合几个电话：

NSUInteger i = [unique indexOfObject:obj];
if ( i != NSNotFound ) {
    [uniqueKind addObject:[NSNumber numberWithInteger:i]];
}
于 2013-08-05T19:33:49.093 回答
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我不确定它是否能解决您的问题，但您是否考虑过使用集合（或可变变体）而不是数组？它们确保唯一性，并允许您检查交叉点/包含。请参阅NSSet 类参考。

于 2013-08-05T19:42:23.307 回答
0

您必须将对象添加到 NSMutableArray，而不是实际的 intValue。尝试先将整数转换为 NSNumber。

[uniqueKind addObject: [NSNumber numberWithInt:i]];

反而。

（已编辑）

于 2013-08-05T19:33:02.593 回答