3

我需要序列化一些数据以作为消息通过 Web 服务传递,该服务将根据模式验证数据。我已经建立了一个对象模型,但我在一个小区域里遗漏了一些东西。

这是架构:

<xs:element name="UserDetailsMessage" minOccurs="0">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="URDUSERDETAILS" minOccurs="0">
        <xs:complexType>
          <xs:sequence>
            <xs:any processContents="skip" maxOccurs="unbounded"/>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
    </xs:sequence>
  </xs:complexType>
</xs:element>

这是我的课:

[Serializable()] public class UserDetailsMessage
{
    private USERDETAILS myUserDetails;

    [XmlElementAttribute("USERDETAILS")]
    public USERDETAILS USERDETAILS {
        get {
            if (myUserDetails == null)
                myUserDetails = new USERDETAILS();
            return this.myUserDetails;
        }
        set { this.myUserDetails = value; }
    }

    public bool URDUSERDETAILSSpecified {
        get {
            if (myUserDetails == null)
                return false;
            return true;
        }
    }

}

[Serializable()] public class USERDETAILS
{
    private List<System.Xml.XmlElement> anyField;

    [XmlAnyElementAttribute(), XmlElementAttribute("Any")]
    public List<System.Xml.XmlElement> Any {
        get { return this.anyField; }
        set { this.anyField = value; }
    }

}

XmlElementAttributeAny元素上使用 an 是为了让它序列化为没有容器的元素序列,但是 XML 输出并没有像我想象的那样出现:

<UserDetailsMessage>
    <USERDETAILS>
        <Any>
            <TEST_DATA_HERE />
        </Any>
    </USERDETAILS>
</UserDetailsMessage>

这导致该XmlDocument.Validate方法输出此验证错误:The 'Any' element is not declared

据我所知,我试图创建的输出应该是这样的:

<UserDetailsMessage>
    <USERDETAILS>
        <TEST_DATA_HERE />
    </USERDETAILS>
</UserDetailsMessage>

是否以某种方式与产生此输出的XmlElementAttribute交互XmlAnyElementAttribute或者我在某处犯了明显的错误?或者,我应该如何序列化没有包含元素的“任何”元素序列?

4

1 回答 1

3

我终于有时间坐下来创建仅关注特定领域的测试项目,并得出以下结论。

<Serializable()> Public Class NotificationMessage

    Private myUserData As UserData

    Public Sub New()
        myUserData = New UserData()
    End Sub

    <System.Xml.Serialization.XmlElementAttribute("UserData")> _
    Public Property UserData() As UserData
        Get
            Return Me.myUserData
        End Get
        Set(value As UserData)
            Me.myUserData = value
        End Set
    End Property

End Class

<Serializable()> Public Class UserData

    Private anyField As List(Of System.Xml.XmlElement)

    Public Sub New()
        Me.anyField = New List(Of System.Xml.XmlElement)()
    End Sub

    <XmlAnyElementAttribute()>
    Public Property Any() As List(Of System.Xml.XmlElement)
        Get
            Return Me.anyField
        End Get
        Set(value As List(Of System.Xml.XmlElement))
            Me.anyField = value
        End Set
    End Property
End Class

这是如果XmlElementXmlAnyElement被组合并应用于 UserData 类的 Any 属性时的输出:

<NotificationMessage>
  <UserData>
    <Any>
      <TEST_DATA_HERE />
    </Any>
  </UserData>
</NotificationMessage>

如果仅XmlElement应用 ,这是输出:

<NotificationMessage>
  <UserData>
    <Any>
      <TEST_DATA_HERE />
    </Any>
  </UserData>
</NotificationMessage>

这是仅XmlAnyElement应用的输出:

<NotificationMessage>
  <UserData>
    <TEST_DATA_HERE />
  </UserData>
</NotificationMessage>

所以我们可以看到,为了序列化“Any”元素序列,我们必须单独使用XmlAnyElement属性。

于 2013-08-09T10:43:05.063 回答