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我有这个输入。

October 21 , 2010
October 14 , 2007
October 08 , 2010
March 19 , 2009
June 25 , 2009
June 21 , 2013
June 21 , 2013
June 19 , 2006
June 01 , 2009
July 26 , 2013
July 25 , 2012
July 23 , 2013
July 19 , 2013
July 01 , 2009
January 31 , 2013
January 23 , 2013
January 23 , 2011
January 19 , 2013
January 01 , 2000
February 17 , 2011
February 16 , 1998
December 25 , 2003
August 31 , 2013
August 04 , 2013
August 03 , 2013
August 03 , 2013
August 03 , 2013
April 26 , 2013
April 26 , 2013
April 19 , 2005

我想订购这个，以便最新日期排在最前面..但我似乎做不到，有人可以提供解决方案吗？

这是我的 sql：

$sql = "SELECT * FROM $tbl_name WHERE Length(Year) > 7 AND `Title` 
LIKE '%" . $q . "%' AND `Genres` LIKE '%" . $genre . "%' AND `Actors` 
LIKE '%" . $actor . "%' AND `Year` <> 'Unknown' 
ORDER BY `Year` DESC LIMIT $start, $limit";
4

2 回答 2

1

所以，这是 2 列，对吧？

然后这样做：

SELECT
STR_TO_DATE(CONCAT(month_day_column, ', ', year_column), '%M %d, %Y') AS your_ISO_conform_date
FROM yourTable
ORDER BY your_ISO_conform_date DESC

  • 阅读更多关于str_to_date() 这里。

  • 以下是有关您必须作为参数提供的格式的一些信息str_to_date()

于 2013-08-05T11:08:10.213 回答
1

我没有在工作中使用 MySQL，主要是 SQL Server，我在一秒钟内找到了这个链接：https ://dev.mysql.com/doc/refman/5.6/en/date-and-time-functions.html #function_str-to-date

select str_to_date('October 21 , 2010', '%M %d,%Y')
于 2013-08-05T11:10:13.290 回答