3

在红宝石中,

"a".next [or] "a".succ # => "b"
"aa".next # => "ab"
"z".next # => "aa" # two a's after one z

如何在 Javascript 中使用它?就像是:

incr_str("aaa") ===> aab
incr_str("zzz") ===> aaaa
4

3 回答 3

4

谷歌搜索“Ruby string succ Javascript”会返回Devon Govett 的这个要点,称为“JavaScript 中 Ruby 的 string.succ 方法的实现”,这似乎是你所追求的......

/*
 * An implementation of Ruby's string.succ method.
 * By Devon Govett
 *
 * Returns the successor to str. The successor is calculated by incrementing characters starting 
 * from the rightmost alphanumeric (or the rightmost character if there are no alphanumerics) in the
 * string. Incrementing a digit always results in another digit, and incrementing a letter results in
 * another letter of the same case.
 *
 * If the increment generates a carry, the character to the left of it is incremented. This 
 * process repeats until there is no carry, adding an additional character if necessary.
 *
 * succ("abcd")      == "abce"
 * succ("THX1138")   == "THX1139"
 * succ("<<koala>>") == "<<koalb>>"
 * succ("1999zzz")   == "2000aaa"
 * succ("ZZZ9999")   == "AAAA0000"
 */

function succ(input) {
  var alphabet = 'abcdefghijklmnopqrstuvwxyz',
    length = alphabet.length,
    result = input,
    i = input.length;

  while(i >= 0) {
    var last = input.charAt(--i),
        next = '',
        carry = false;

    if (isNaN(last)) {
        index = alphabet.indexOf(last.toLowerCase());

        if (index === -1) {
            next = last;
            carry = true;
        }
        else {
            var isUpperCase = last === last.toUpperCase();
            next = alphabet.charAt((index + 1) % length);
            if (isUpperCase) {
                next = next.toUpperCase();
            }

            carry = index + 1 >= length;
            if (carry && i === 0) {
                var added = isUpperCase ? 'A' : 'a';
                result = added + next + result.slice(1);
                break;
            }
        }
    }
    else {
        next = +last + 1;
        if(next > 9) {
            next = 0;
            carry = true
        }

        if (carry && i === 0) {
            result = '1' + next + result.slice(1);
            break;
        }
    }

    result = result.slice(0, i) + next + result.slice(i + 1);
    if (!carry) {
        break;
    }
  }
  return result;
}
于 2013-08-05T05:19:32.590 回答
1

我找到了 RubyJs 库。请检查一下。

http://rubyjs.org/

<script src="ruby.min.js"></script>
<script>
var str = R("aaa");
alert(str.next());
</script>
于 2013-08-05T05:15:49.420 回答
0

String.fromCharCode()和的组合"".charCodeAt()应该相当直接地实施。

var FIRST = 97,
    LAST = 122;

function next (string) {
  var lastChar = string[string.length - 1];

  string = string.substring(0, string.length - 1);

  if(lastChar.charCodeAt(0) >= LAST) {
    // make last char a and append a
    lastChar = String.fromCharCode(FIRST) + String.fromCharCode(FIRST);
  }
  else {
    // Increase last char
    lastChar = String.fromCharCode(lastChar.charCodeAt(0) + 1);
  }

  return string + lastChar;
}

非常快速和肮脏并且行为有点奇怪(zzz -> zzaa 而不是 zaaa 或 zzza,不确定哪种行为是最好的),但它显示了你如何去实现它(而且 atm 我没有时间写一个更精致的答案)。

于 2013-08-05T06:52:41.193 回答