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我想要做的是将文本文件中的每一行插入到 mysql 数据库的新行中。我究竟做错了什么？

我有一个类似于以下内容的文本文件。

11111,customer1
11112,customer2
11113,customer3
11114,customer4

我的 MySQL 数据库有字段 id、number、customer

我的 php 代码不起作用，如下所示。

<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");

    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 

    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
$sql="INSERT INTO list (number, customer) VALUES ('$_POST[number]','$_POST[customer]')";
if (!mysqli_query($con,$sql))
  {
  die('Error: ' . mysqli_error());
  }

mysqli_close($con);
}
?>
</table>
<input type="submit" value="Submit File" />
</form>
</body>
</html>
4

5 回答 5

4

您的值在数组中$arrM而不是在$_POST. 请试试这个：

$sql="INSERT INTO list (number, customer) VALUES ('$arrM[0]','$arrM[1]')";

此外，您要确保$sql在循环中运行它。

于 2013-08-05T03:29:10.057 回答
1

您的代码中有多个问题。如果您只想从文本文件中插入，可以尝试以下操作

<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");
    $arr_to_insert = array();
    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>';
       //strore text file row to an array 
       $arr_to_insert[] = $arrM;
    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
foreach($arr_to_insert as $ai){
    $sql="INSERT INTO list (number, customer) VALUES ('{$ai[0]}','{$ai[1]}')";
    if (!mysqli_query($con,$sql))
      {
      die('Error: ' . mysqli_error());
      }

}
mysqli_close($con);
}
?>
</table>
</form>
</body>
</html>

注释了问题的代码的原始版本。

<html>
<head>
<title>Add File To DB</title>
</head>

<body>
<form action="list.php" method="post">
<input type="submit" value="Submit File" />
<table>

<?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");
    // you need to strore text file row to an array to later insert to database.
    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); //$arrM is private inside while loop.
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 

    }

    fclose($f);
if (isset($_POST['submit'])) {
include 'connection.php';
//you are trying to insert $_POST[number] and $_POST[customer] which are non-existent
//also you need to loop through the rows in your text file and store each row.
$sql="INSERT INTO list (number, customer) VALUES ('$_POST[number]','$_POST[customer]')";
if (!mysqli_query($con,$sql))
  {
  die('Error: ' . mysqli_error());
  }

mysqli_close($con);
}
?>
</table>
<!-- duplicate submit button -->
<input type="submit" value="Submit File" />
</form>
</body>
</html>

PS：请注意，我只是指出您的代码中的错误并按原样进行修复。我不是想优化它。看起来您正在尝试学习 PHP，而不是获得更好的解决方案。

于 2013-08-05T04:08:12.050 回答
0

您的脚本存在多个问题。

  1. 首先，您正在使用$_POST['submit']但尚未name='submit'在提交按钮中使用。
  2. 正如@vinod 所说，您的值在数组$arrM not in$_POST` 中。

现在您需要在循环中插入数据。确保只包含一次连接，并在所有数据库操作完成后关闭连接。

<html>
 <head>
  <title>Add File To DB</title>
 </head>

 <body>
  <form action="list.php" method="post">
  <input type="submit" name='submit' value="Submit File" /> <!-- Provide name `submit` to your button so that you can access $_POST['submit'] -->
  <table>

  <?php
    $f = fopen("textfile.txt", "r") or exit("Unable to open file!");

    //include your connection around here so it is included only once
    include "connection.php";

    // Read line by line until end of file
    while (!feof($f)) { 

    // Make an array using comma as delimiter
       $arrM = explode(',',fgets($f)); 
    // Write links (get the data in the array)
       echo '<tr><td name="number">' . $arrM[0] . '</td><td name="customer">' . $arrM[1] . '</td></tr>'; 
       if (isset($_POST['submit'])) {               
            $sql = "INSERT INTO list (number, customer) VALUES ('$arrM[0]','$arrM[0]')"; //here should be $arrM
            if (!mysqli_query($con,$sql)) {
              die('Error: ' . mysqli_error());
            }               
        }
    }

    fclose($f);
    mysqli_close($con); //close your database connection here
  ?>
 </table>
 <!--<input type="submit" value="Submit File" />-->
 </form>
 </body>
</html>
于 2013-08-05T04:11:12.687 回答
0 
If you want to insert data of the text file into the database then you can do this.
<?php   
include('dbcon.php');
$file_content=explode("\n",file_get_contents("demo.txt"));//write your text file name instead of demo.txt   
for($i=0;$i<count($file_content)-1;$i++){
    $exploded_content=explode(",",$file_content[$i]);
    $q=mysqli_query($con,"insert into demo (id,name) values('$exploded_content[0]','$exploded_content[1]')");
         //put your table name instead of demo it has two columns id and name
}

?>
Below is the dbcon.php file
// Create connection
$con=mysqli_connect("localhost","user","pass","dbname");
//put your host user pass database name above i put it dummy
// Check connection
if (mysqli_connect_errno($con))
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }
于 2013-08-05T04:22:30.773 回答
0

您必须正确插入值

$sql="INSERT INTO list (number, customer) VALUES ('".$arrM[0]."','".$arrM[1]."')";
于 2018-06-06T04:55:19.547 回答