28

有谁知道如何将一个添加ArrayList<NameValuePair>到一个 Intent 作为额外的？

ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("first_name", first_name));
nameValuePairs.add(new BasicNameValuePair("last_name", last_name));
nameValuePairs.add(new BasicNameValuePair("email", email));
nameValuePairs.add(new BasicNameValuePair("password", password));

/* Move on to step 2 */
Intent intent = new Intent(RegisterActivity1.this, RegisterActivity2.class);
intent.putExtra("nvp", nameValuePairs);
startActivity(intent);

这是 RegisterActivity2 的类声明：

public class RegisterActivity2 extends Activity implements Serializable {
}

logcat中的错误是：

> Parcel: unable to marshal value first_name="whatever"

实施 Ted Hopp 的建议后，我仍然收到错误消息。这是堆栈跟踪：

08-04 22:10:16.095: E/AndroidRuntime(5065): FATAL EXCEPTION: main
> 08-04 22:10:16.095: E/AndroidRuntime(5065):
> java.lang.RuntimeException: Unable to start activity
> ComponentInfo{/.RegisterActivity2}: java.lang.RuntimeException:
> Parcelable encountered IOException reading a Serializable object (name
> = database.NVP) 08-04 22:10:16.095: E/AndroidRuntime(5065):   at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2070)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2095)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> android.app.ActivityThread.access$600(ActivityThread.java:135) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.app.ActivityThread$H.handleMessage(ActivityThread.java:1201)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> android.os.Handler.dispatchMessage(Handler.java:99) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.os.Looper.loop(Looper.java:137) 08-04 22:10:16.095:
> E/AndroidRuntime(5065):   at
> android.app.ActivityThread.main(ActivityThread.java:4849) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> java.lang.reflect.Method.invokeNative(Native Method) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> java.lang.reflect.Method.invoke(Method.java:511) 08-04 22:10:16.095:
> E/AndroidRuntime(5065):   at
> com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:795)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> com.android.internal.os.ZygoteInit.main(ZygoteInit.java:562) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> dalvik.system.NativeStart.main(Native Method) 08-04 22:10:16.095:
> E/AndroidRuntime(5065): Caused by: java.lang.RuntimeException:
> Parcelable encountered IOException reading a Serializable object (name
> = database.NVP) 08-04 22:10:16.095: E/AndroidRuntime(5065):   at android.os.Parcel.readSerializable(Parcel.java:2144) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.os.Parcel.readValue(Parcel.java:2016) 08-04 22:10:16.095:
> E/AndroidRuntime(5065):   at
> android.os.Parcel.readListInternal(Parcel.java:2235) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.os.Parcel.readArrayList(Parcel.java:1655) 08-04 22:10:16.095:
> E/AndroidRuntime(5065):   at
> android.os.Parcel.readValue(Parcel.java:1986) 08-04 22:10:16.095:
> E/AndroidRuntime(5065):   at
> android.os.Parcel.readMapInternal(Parcel.java:2226) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.os.Bundle.unparcel(Bundle.java:223) 08-04 22:10:16.095:
> E/AndroidRuntime(5065):   at
> android.os.Bundle.getSerializable(Bundle.java:1254) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.content.Intent.getSerializableExtra(Intent.java:4268) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> .RegisterActivity2.onCreate(RegisterActivity2.java:24) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.app.Activity.performCreate(Activity.java:5244) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     at
> android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1082)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2034)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   ... 11 more 08-04
> 22:10:16.095: E/AndroidRuntime(5065): Caused by:
> java.io.InvalidClassException:
> org.apache.http.message.BasicNameValuePair; IllegalAccessException
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> java.io.ObjectStreamClass.resolveConstructorClass(ObjectStreamClass.java:694)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> java.io.ObjectStreamClass.newInstance(ObjectStreamClass.java:655)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> java.io.ObjectInputStream.readNewObject(ObjectInputStream.java:1816)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:787)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> java.io.ObjectInputStream.readObject(ObjectInputStream.java:2003)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> java.io.ObjectInputStream.readObject(ObjectInputStream.java:1960)
> 08-04 22:10:16.095: E/AndroidRuntime(5065):   at
> android.os.Parcel.readSerializable(Parcel.java:2142) 08-04
> 22:10:16.095: E/AndroidRuntime(5065):     ... 23 more
4

5 回答 5

24

正如其他人所指出的，当您想将数组作为额外的意图传递时，元素需要实现Serializable. 在您的情况下，该方法相当简单（不完全 - 见下文）：定义您自己的子类BasicNameValuePair并声明它以实现接口。

public class NVP extends BasicNameValuePair implements Serializable {
    public NVP(String name, String value) {
        super(name, value);
    }
}

然后你可以像你一直在尝试的那样使用它：

ArrayList<NVP> nameValuePairs = new ArrayList<NVP>();
nameValuePairs.add(new NVP("first_name", first_name));
nameValuePairs.add(new NVP("last_name", last_name));
nameValuePairs.add(new NVP("email", email));
nameValuePairs.add(new NVP("password", password));

/* Move on to step 2 */
Intent intent = new Intent(RegisterActivity1.this, RegisterActivity2.class);
intent.putExtra("nvp", nameValuePairs);
startActivity(intent);

在接收端，您需要将其拉出：

ArrayList<NVP> nameValuePairs = (ArrayList<NVP>) intent.getSerializable("nvp");

编辑好吧，上面的内容不起作用，因为BasicNameValuePair没有默认构造函数，并且序列化机制要求不可序列化的祖先类具有默认构造函数。否则，您将在反序列化时遇到异常。

不幸的是，这意味着解决方案并不像我想象的那么简单。一种解决方法是定义您自己的类来实现Parcelable，正如@keerthana murugesan 在他的回答中所建议的那样。如果你以前实现Parcelable过，你就会知道这有点痛苦。另一种解决方法是定义一个包装 a BasicNameValuePair（而不是从它派生）并管理其自己的序列化的类：

public class NVP implements NameValuePair, Serializable {
    private BasicNameValuePair nvp;

    public NVP(String name, String value) {
        nvp = new BasicNameValuePair(name, value);
    }

    @Override
    public String getName() {
        return nvp.getName();
    }

    @Override
    public String getValue() {
        return nvp.getValue();
    }

    // serialization support

    private static final long serialVersionUID = 1L;

    private void writeObject(ObjectOutputStream out) throws IOException {
        out.writeString(nvp.getName());
        out.writeString(nvp.getValue());
    }

    private void readObject(ObjectInputStream in) throws IOException, ClassNotFoundException {
        nvp = new BasicNameValuePair(in.readString(), in.readString());
    }

    private void readObjectNoData() throws ObjectStreamException {
        // nothing to do
    }
}
于 2013-08-05T03:33:44.670 回答
23

我有同样的问题，试图在 ArrayList 中发送对象而不在 Object 类中实现 Seiralizable。

捷径的解决方案是将 ArrayList 封装在 Bundle 中。

所以，在第一个活动中->

ArrayList<Object> objects = new ArrayList<Object>(); 
// Object class does not implement Serializable interface

Bundle extra = new Bundle();
extra.putSerializable("objects", objects);

Intent intent = new Intent(getBaseContext(), ShowSpread.class);
intent.putExtra("extra", extra);

第二个活动->

Bundle extra = getIntent().getBundleExtra("extra");
ArrayList<Object> objects = (ArrayList<Object>) extra.getSerializable("objects")

工作正常。

于 2014-07-22T21:49:25.773 回答
1

您需要将 Object 数组作为 Serializable 传递到意图中。Object 数组必须由可序列化的对象组成。

ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("first_name", first_name));
nameValuePairs.add(new BasicNameValuePair("last_name", last_name));
nameValuePairs.add(new BasicNameValuePair("email", email));
nameValuePairs.add(new BasicNameValuePair("password", password));

这里BaseNameValuePair需要一个实现Serializable. 使用into put，并将toArray其类型转换为. 在你的 getter Activity上使用 Intent 方法。ArrayListSerializablegetSerializable

于 2013-08-05T03:25:07.027 回答
0

为此，您的 List 拥有的泛化类型必须实现Serializable.

于 2013-08-05T03:06:43.293 回答
0

这可以使用Parcelable接口来实现。

  1. 使您的BasicNameValuePair类实现Parcelable接口。有关更多参考，请参阅此内容。

    public class BasicNameValuePair implements Parcelable{

}

  2. ArrayList像上面那样将这些对象添加到

    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("first_name", first_name));
nameValuePairs.add(new BasicNameValuePair("last_name", last_name));
nameValuePairs.add(new BasicNameValuePair("email", email));
nameValuePairs.add(new BasicNameValuePair("password", password));

  3. 将这些传递给intentusing putParcelableArrayListExtra()。

    intent.putParcelableArrayListExtra ("nvp", nameValuePairs);
startActivity(intent);
于 2013-08-05T03:31:36.300 回答