4

我正在尝试使用 swing 编写井字游戏程序,但我似乎遇到了一些麻烦。在我的匿名内部类中,我尝试为每个按钮设置 actionListener,但我无法找到允许我引用按钮并将它们设置为 X 或 Y 的类型或变量。我试过 e .getSource().setText() 在我的匿名类中,但返回错误。有什么想法吗?谢谢!亚历克斯

import javax.swing.*;

import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

public class TicTacToe  {

public JFrame frame;
public JLabel label;
public JPanel panel;

public static int counter;



public void go()
{ 
    frame = new JFrame("TicTacToe");
    frame.setSize(500, 500);
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    panel = new JPanel();
    panel.setLayout(new GridLayout(3,3,10,10));
    frame.add(BorderLayout.CENTER, panel);
    label= new JLabel("TIC TAC TOE");
    frame.add(BorderLayout.NORTH, label);

    ; 


    JButton button1 = new JButton("Button 1");
    JButton button2 = new JButton("Button 1");
    JButton button3 = new JButton("Button 1");
    JButton button4 = new JButton("Button 1");
    JButton button5 = new JButton("Button 1");
    JButton button6 = new JButton("Button 1");
    JButton button7 = new JButton("Button 1");
    JButton button8 = new JButton("Button 1");
    JButton button9 = new JButton("Button 1");





    button1.addActionListener(new ActionListener(){ 
        public void actionPerformed(ActionEvent e)
        {


        }
    });

    button2.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button3.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button4.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button5.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button6.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button7.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button8.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    button9.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e)
        {

        }
    });

    panel.add(button1);
    panel.add(button2);
    panel.add(button3);
    panel.add(button4);
    panel.add(button5);
    panel.add(button6);
    panel.add(button7);
    panel.add(button8);
    panel.add(button9);
    frame.setVisible(true);
    panel.setVisible(true);

}


public static void main(String[] args)
{
    TicTacToe gui = new TicTacToe();
    gui.go();

}


}
4

3 回答 3

12

请记住,ActionListener可以在许多不同类型的组件上使用,因此源引用是通用的。您需要转换回预期值

button9.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e)
    {
        Object source = e.getSource();
        if (source instanceof JButton) {
            JButton btn = (JButton)source;
            // Go ahead and do what you like
        }
    }
});

虽然我知道你ActionListener现在的情况几乎可以保证源类型Object将是 a JButton,但我从不喜欢盲目地投射对象,但那就是我

于 2013-08-05T02:22:22.487 回答
2

如果您收到错误,那么您应该发布它们,但我假设这是因为您没有断言源对象实际上是一个按钮。您正在做的事情有两种直接的解决方案。

首先是因为您只为每个按钮添加一个动作侦听器,您可以假设它是动作事件所引用的对象。请注意,按钮需要是实例变量或声明为 final:

    button1.addActionListener(new ActionListener(){ 
        @Override
        public void actionPerformed(ActionEvent e)
        {
            button1.setText("X/Y");
        }
    });

其次,通过断言 ActionEvent 源对象实际上是一个按钮来解决您的错误原因。这是通过检查源是 JButton 的一个实例来完成的:

    button1.addActionListener(new ActionListener() {
        @Override
        public void actionPerformed(ActionEvent e) {
            if (e.getSource() instanceof JButton) {
                ((JButton) e.getSource()).setText("X/Y");
            }
        }
    });
于 2013-08-05T02:22:43.417 回答
1

我浏览并清理了你的代码。我不太确定你的代码为什么有错误,但我没有得到任何错误。我建议,因为你有通用代码,所以像我在数组中一样重用它。我还添加了一个boolean在每个按钮单击时在玩家之间切换。

最后,我建议在构造函数中设置 JFrame,或者在构造函数调用的私有方法中设置(更复杂的用户界面可能有很多代码,分解它是代码可维护性的好习惯),就像我展示的那样以下。

import javax.swing.*;

import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

public class TicTacToe {
    public static final boolean PLAYER_X = false;
    public static final boolean PLAYER_O = true;

    public static int counter;

    private JFrame frame;
    private JLabel label;
    private JPanel panel;
    private JButton[] buttons;
    private boolean player;

    public TicTacToe() {
        frame = new JFrame("TicTacToe");
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

        panel = new JPanel();
        panel.setPreferredSize(new Dimension(500, 500));
        panel.setLayout(new GridLayout(3, 3, 10, 10));
        frame.add(BorderLayout.CENTER, panel);

        label = new JLabel("TIC TAC TOE");
        frame.add(BorderLayout.NORTH, label);

        /* Set the initial player turn to player X */
        player = PLAYER_X;

        /* Create the JButtons  */
        buttons = new JButton[9];

        /* Loop through and set all of them up */
        for (int i = 0; i < buttons.length; i++) {
            buttons[i] = new JButton();
            buttons[i].addActionListener(new ActionListener() {
                @Override
                public void actionPerformed(ActionEvent e) {
                    if (e.getSource() instanceof JButton) {
                        ((JButton)e.getSource()).setText(player ? "O" : "X"); /* Set button text */
                        player = !player; /* Switch turns */
                    }
                }
            });

            /* Add all of the buttons to the panel. */
            panel.add(buttons[i]);
        }

        /* Pack the frame to the contents. Basically a "fit to contents". */
        frame.pack();
    }

    public void go() {
        frame.setVisible(true);
        panel.setVisible(true);
    }

    public static void main(String[] args) {
        TicTacToe gui = new TicTacToe();
        gui.go();
    }
}
于 2013-08-05T02:29:09.420 回答