我有类称为数据库这里的语法
<?php
class Database
{
var $conn = null;
var $config = array(
'username' => 'root',
'password' => '',
'hostname' => 'localhost',
'database' => '<dbname here>'
);
function __construct() {
$this->connect();
echo 'constructor database';
}
function connect() {
if (is_null($this->conn)) {
$db = $this->config;
$this->conn = mysql_connect($db['hostname'], $db['username'], $db['password']);
if(!$this->conn) {
die("Cannot connect to database server");
}
if(!mysql_select_db($db['database'])) {
die("Cannot select database");
}
}
return $this->conn;
}
}
我已经将此数据库文件包含到另一个 php 类中，假设它是 authenticate.php
include $_SERVER['DOCUMENT_ROOT'].'/<project_name>/configuration/database.php';
哪个类是：
class authenticate {
public function __construct() {
$db = new Database();
$db->connect();
}
public function auth($username, $password) {
$password = $this->HASH($username, $password);
$query = "SELECT username, password FROM mt_user WHERE username = '$username' AND password='$password' LIMIT 1";
$row = mysql_query($query) or die(mysql_error());
$result = mysql_num_rows($row);
if ($result != 1) {
$status_login = "FALSE";
} else
if ($result == 1) {
$status_login = "TRUE";
}
mysql_close();
return $status_login;
}
public function getSalt($username) {
$query = "SELECT salt FROM mt_user WHERE username = '$username'";
$result = mysql_query($query);
$salt = array();
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$salt = $row['salt'];
}
mysql_close();
return reset($salt);
}
public function HASH($username,$password){
$salt = $this->getSalt($username);
$output = sha1($salt.$password);
return $output;
}
}
?>
我将该函数调用到名为 login.php 的某个视图，但它在 authenticate.php 上抛出“无法选择数据库”或无法连接到数据库的错误。
这个 authenticate 或 database.php 文件有什么问题？
谢谢你。