我得到的答复是时间格式,例如
ScheduleDate = "\/Date(1374811200000-0400)\/"
StartTime = "\/Date(-2208931200000-0500)\/"
我怎样才能将上述时间转换为格式
"2012-01-01T10:30:00-05:00"
我得到的答复是时间格式,例如
ScheduleDate = "\/Date(1374811200000-0400)\/"
StartTime = "\/Date(-2208931200000-0500)\/"
我怎样才能将上述时间转换为格式
"2012-01-01T10:30:00-05:00"
这是我想出的,但是您的示例输入都与您的示例输出不匹配,所以我不确定这里是否存在时区偏移错误。
#!/usr/bin/env python
import datetime
def parse_date(datestring):
timepart = datestring.split('(')[1].split(')')[0]
milliseconds = int(timepart[:-5])
hours = int(timepart[-5:]) / 100
time = milliseconds / 1000
dt = datetime.datetime.utcfromtimestamp(time + hours * 3600)
return dt.strftime("%Y-%m-%dT%H:%M:%S") + '%02d:00' % hours
ScheduleDate = "\/Date(1374811200000-0400)\/"
StartTime = "\/Date(-2208931200000-0500)\/"
print(parse_date(ScheduleDate))
print(parse_date(StartTime))
Windows 似乎不喜欢datetime.(utc)?fromtimestamp()
. 可以要求它计算 Unix 纪元的负时间增量:
#!/usr/bin/env python
import datetime
EPOCH = datetime.datetime.utcfromtimestamp(0)
def parse_date(datestring):
timepart = datestring.split('(')[1].split(')')[0]
milliseconds = int(timepart[:-5])
hours = int(timepart[-5:]) / 100
adjustedseconds = milliseconds / 1000 + hours * 3600
dt = EPOCH + datetime.timedelta(seconds=adjustedseconds)
return dt.strftime("%Y-%m-%dT%H:%M:%S") + '%02d:00' % hours
ScheduleDate = "\/Date(1374811200000-0400)\/"
StartTime = "\/Date(-2208931200000-0500)\/"
print(parse_date(ScheduleDate))
print(parse_date(StartTime))