29

当我尝试运行以下函数时，我收到错误“SQLSTATE [HY093]：无效参数号”：

function add_persist($db, $user_id) {
    $hash = md5("per11".$user_id."sist11".time());
    $future = time()+(60*60*24*14);
    $sql = "INSERT INTO persist (user_id, hash, expire) VALUES (:user_id, :hash, :expire) ON DUPLICATE KEY UPDATE hash=:hash";
    $stm = $db->prepare($sql);
    $stm->execute(array(":user_id" => $user_id, ":hash" => $hash, ":expire" => $future));
    return $hash;
}

我觉得这很简单，我只是没有抓住。有任何想法吗？

4

4 回答 4

47

尝试：

$sql = "INSERT INTO persist (user_id, hash, expire)
        VALUES (:user_id, :hash, :expire)
        ON DUPLICATE KEY UPDATE hash=:hash2";

和

$stm->execute(
    array(":user_id" => $user_id, 
          ":hash" => $hash, 
          ":expire" => $future,
          ":hash2" => $hash)
);

文档摘录（http://php.net/manual/en/pdo.prepare.php）：

当您调用 PDOStatement::execute() 时，您必须为希望传递给语句的每个值包含一个唯一的参数标记。您不能在准备好的语句中两次使用同名的命名参数标记。您不能将多个值绑定到单个命名参数，例如 SQL 语句的 IN() 子句。

于 2013-08-03T02:40:57.703 回答
17

This is one limitation to using PDO. PDO simply acknowledges the number of parameters in the query and the execution and throws an error on any mismatch. If you need to use parameter repetition in your queries, you have to go about it using a workaround

$sql = "insert into persist(user_id, hash, expire) values
    (:user_id, :hash, :value) on duplicate key update
    hash = :hash2";
$stm->execute(array(':user_id' => $user_id, ':hash' => $hash, ':hash2' => $hash,
    ':expire' => $expire));

You can refer to this for a more elaborate workaround - https://stackoverflow.com/a/7604080/1957346

于 2013-08-03T02:45:39.123 回答
5

我知道这是一个老问题，但是我认为值得注意的是，更合适的解决方案是通过适当地利用 SQL 来避免 PHP 中笨拙的解决方法：

INSERT INTO `persist` (`user_id`, `hash`, `expire`)
VALUES (:user_id, :hash, :expire)
ON DUPLICATE KEY UPDATE `hash`=VALUES(`hash`)

这样，您只需发送一次值。

于 2017-04-04T05:54:54.510 回答
-2 
$stmt = $con->prepare("INSERT INTO items(Name, Description, Price, Country_Made, Status, Add_Date)  VALUES( :zname, :zdesc, :zprice, :zcountry, zstatus, now())");

$stmt-> execute(array(
   "zname" => $name,
   "zdesc" => $desc,
   "zprice" => $price,
   "zcountry" => $country,
   "zstatus" => $status 
));
于 2016-09-27T06:33:01.220 回答