我创建了一个连接到我的数据库的脚本,名为 mysqlconnecter:
<?php
define("DB_USERNAME", "root");
define("DB_PASSWORD", "pass");
define("DB_DATABASE", "adventure_of_dragons");
define("DB_SERVER", "127.0.0.1");
$db_handle = mysql_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
$db_found = mysql_select_db(DB_DATABASE, $db_handle);
if ($db_found || true) {
$SQL = "SELECT * FROM members";
$result = mysql_query($SQL) or die(mysql_error());
while ( $row = mysql_fetch_assoc($result) ) {
$id = $row['member_id'];
$username = $row['username'];
$password = $row['password'];
$rank = $row['rank'];
}
mysql_close($db_handle);
} else {
echo "Database NOT Found " . $db_handle;
}
?>
然后我创建了另一个包含 mysqlconnecter.php 的脚本并将数据发布到数据库中:
<?php
include "mysqlconnecter.php";
echo 'ID = ' . $id . '<br>';
echo 'RANK = ' . $rank . '<br>';
echo 'USERNAME = ' . $username . '<br>';
echo 'PASSWORD = ' . $password . '<br><br>';
// two <br>'s, so we get an empty line between users
?>
但输出显示数据库内的数据两次:
ID = 4
RANK = 100
USERNAME = user
PASSWORD = password
ID = 4
RANK = 100
USERNAME = user
PASSWORD = password
我只希望它显示一次文本,我该怎么办?