我遇到了一个错误，我一生都无法弄清楚。我的代码有点乱，所以要小心：
$hostname = ""; //SET SERVER/HOSTNAME
$dbusername = ""; //SET DATABASE USERNAME
$dbname = ""; //SET DATABASE NAME
$dbpassword = ""; //SET DATABASE USERNAME
$link = mysqli_connect($hostname, $dbusername, $dbpassword, $dbname);
if (!$link) {
die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error());
}
$sql = "SELECT * FROM utility WHERE `program_code` = '$program_code'";
$result = mysqli_query($link, $sql, MYSQLI_USE_RESULT);
if (!$result)
{
echo 'Error: ', $mysqli->error;
}
while($row = $result->fetch_assoc()){
$program_code1 = $row['program_code'];
$utility_company = $row['utility_company'];
$rate = $row['rate'];
$term = $row['term'];
}
$sql1 = "INSERT INTO v88374 (id, ldc_account_num, revenue_class_desc, first_name, last_name, home_phone_num, sline1_addr, scity_name, spostal_code, marketer_name, distributor_name, service_type_desc, bill_method, enroll_type_desc, requested_start_date, plan_desc, contract_start_date, contract_end_date, fixed_commodity_amt, vendor_id, office_id, agent_id, customer_name, contact_name, result, promo_code, validation_code, email, state, bname, baddress, program_code, date) VALUES ( '','$ldc_account_num1','$revenue_class_desc','$first_name1','$last_name1', '$home_phone_num1','$sline1_addr1','$scity_name1','$spostal_code1','','$utility_company','$service_type_desc','$bill_method','$enroll_type_desc','$requested_start_date','$plan_desc','$contract_start_date','$contract_end_date','$rate','$vendor_id','$office_id','$agent_id1','$customer_name','$contact_name','$result','$promo_code','$validation_code1','$email1','$state1','$bname1','$baddress1','$program_code1', now())";
$result1 = mysqli_query($link, $sql1, MYSQLI_STORE_RESULT);
if (!$result1)
{
echo 'Error: ', $mysqli->error;
}
else if ($result1){
echo "Thank you. Information submitted.";
}
当我的第二个 sql 语句开始时，我收到错误（在这个问题的主题中），在 $sql1 = long_string_of_code 我认为这可能与我的第一个语句中的变量有关？如果我从第一个语句中回显我的变量，我会得到它们。所以我不确定这笔交易是什么。任何帮助表示赞赏，我知道这是很多代码。谢谢你。