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有问题的代码和'this here ...因为仅通过更改PfUser User中的参数PfUser Current User，应用程序不会产生问题...我忘记指出崩溃的类型...

-(void) {RichiamaDatiInattesa


PFQuery *EsamiInAttesa = [PFQuery queryWithClassName: @ "EsamiInAttesa"];

[EsamiInAttesa whereKey: @ "user" equalTo: [PFUser currentUser]];** //This is the problem Crash "Equal To: [PFUser currentUser]

[EsamiInAttesa countObjectsInBackgroundWithTarget: self selector: @ selector (countcallback: error :)];}

这会返回日志的崩溃

U 03/08/2013 00:04:10.650 [20120:907]将应用程序二终止为未捕获的异常“NSInvalidArgumentException”，原因：“无法对查询类型进行比较：（null）” First throw call stack: (0x31a703e7 0x3976b963 0x31a70307 0xcdb6b 0xbba53 0xa939d 0xa9117 0x3389e579 0x338ded59 0x338daaf5 0x3391c1e1 0x338df803 0x338d7833 0x3387fd1f 0x3387f7ad 0x3387f1ef 0x355975f7 0x35597227 0x31a453e7 0x31a4538b 0x31a4420f 0x319b723d 0x319b70c9 0x338d646d 0x338d32b9 0xa89bd 0x39b98b20) libc + + abi.dylib: terminate called throwing an exception

///////////////////////////////////////// /////////////////////////////////

我正在工作 PARSE（壮观），但我无法弄清楚我错在哪里，因为我不断地从这个 CRASH.... :(

终止两个未捕获的异常'NSInvalidArgumentException'，原因：'无法对查询类型进行比较：（null）'

如果我在[PFUser用户]中修改这个查询“等于[PFUser当前用户]不会返回应用程序问题并且它工作正常，除了当我打开应用程序时，第一页我需要你给我值​​​​当前用户，如果不是当前用户只插入用户，这是不可能的...

问题发生在我运行LOGOUT的时候用户又尝试再次登录...此时应用程序崩溃...连屏幕都没有显示PF登录

代码'this，你能告诉我哪里错了吗？谢谢大家

- (void) {RichiamaDatiInattesa
    
PFQuery EsamiInAttesa * = [PFQuery queryWithClassName: @ "EsamiInAttesa"];
     [EsamiInAttesa whereKey: @ "user" equalTo: [PFUser currentUser]];
     [EsamiInAttesa countObjectsInBackgroundWithTarget: self selector: @ selector (countcallback: error :)];
}


- (void) countcallback: (NSNumber *) count error: (NSError *) error {
     if (error) {
         self.DisplayNumero.text = [NSString stringWithFormat: @ "% d tests are currently pending," [count intValue]];
          

     Else {}

         self.DisplayNumero.text = [NSString stringWithFormat: @ "Connection Absent"];
        / * [[[UIAlertView alloc] initWithTitle: @ "Missing Information"
                                     message: @ "Make sure you fill out all of the information!"
                                    delegate: nil
                           cancelButtonTitle: @ "ok"
                           otherButtonTitles: nil] show]; * /
        }

    
}
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1 回答 1

4

在尝试执行任何需要用户的操作之前，您需要检查当前是否有登录用户。如果[PFUser currentUser] == nil那么你不应该创建并尝试运行你的PFQuery，因为没有当前用户来生成它。

你可以试试：

- (void)RichiamaDatiInattesa {
    if ([PFUser currentUser] != nil) {
        PFQuery EsamiInAttesa * = [PFQuery queryWithClassName: @ "EsamiInAttesa"];
        [EsamiInAttesa whereKey: @ "user" equalTo: [PFUser currentUser]];
        [EsamiInAttesa countObjectsInBackgroundWithTarget: self selector: @ selector (countcallback: error :)];
    } else {
        [self countcallback:0 error:nil];
    }
}

当用户登录时，确保RichiamaDatiInattesa在登录完成后调用该方法（如果它在后台完成）。

于 2013-08-02T22:52:54.307 回答